1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnom [1K]
3 years ago
8

Time Dilation. A group of scientists discover a new, rare isotope and are able to store a small amount of it. They determine tha

t the isotope is unstable and half of their sample will decay in 13.0 monthsmonths . The scientists need a new laboratory to properly conduct measurements on the isotope. If laboratory is built before half the sample decays there will still be enough of the isotope available for experiments. However, it will take 21.0 monthsmonths to build the new lab. Fortunately, the scientists can quickly start construction and they have access to a spaceship that can travel at speeds approaching the speed of light c = 3.00
Physics
1 answer:
Paraphin [41]3 years ago
8 0

This question is incomplete, the complete question is;

Time Dilation. A group of scientists discover a new, rare isotope and are able to store a small amount of it. They determine that the isotope is unstable and half of their sample will decay in 13.0 months . The scientists need a new laboratory to properly conduct measurements on the isotope. If laboratory is built before half the sample decays there will still be enough of the isotope available for experiments. However, it will take 21.0 months to build the new lab. Fortunately, the scientists can quickly start construction and they have access to a spaceship that can travel at speeds approaching the speed of light c = 3.00 x 10⁸ m/s.

If they place their sample of the isotope on the spaceship, at what speed must it travel in order for the new laboratory to be completed on Earth by the time half of the isotope on the spaceship decays? Assume that it took one month for the scientists to actually start construction and launch the spaceship so half the sample will remain in 12.0 months but it will still take 21.0 months to build the new lab.

Answer:

the required speed is 2.4618 x 10⁸ m/s

Explanation:

Given the data in the question;

Time taken to complete a lab = 21 months  

it took them one one to actually start so

Time remaining so that sample only decays by 1/2 = (13 - 1) = 12 months

we need to find at what speed the spaceship should travel so that time on earth ( = 12 months) become time on spaceship ( = 21 months)

we make use of time dilation equation;

t' = t/√( 1 - v²/c² )

where t is time in rest frame = 12 and t' is time in moving frame = 21

so we substitute

21 = 12/√( 1 - v²/c² )

21√( 1 - v²/c² ) = 12

√( 1 - v²/c² ) = 12/21

we square both side

( 1 - v²/c² ) = ( 12/21 )²

( 1 - v²/c² ) = 0.3265

v²/c² = 1 - 0.3265

v²/c² = 0.6735

v² = 0.6735 × c²

v = √0.6735 × √c²

v = 0.8206 × c

given that speed of light c = 3 x 10⁸ m/s

v = 0.8206 × 3 x 10⁸ m/s

v = 2.4618 x 10⁸ m/s

Therefore, the required speed is 2.4618 x 10⁸ m/s

You might be interested in
You have a nightlight plugged into an outlet in the hallway, which uses 3.5 watts when plugged in. If the house circuit provides
marusya05 [52]

Answer:

I = 0.029 A

Explanation:

It is given that,

Power of hallway is 3.5 watts

The  house circuit provides 120 volts

We need to find the current through this bulb. The power of electric bulb is given by :

P=VI

I=\dfrac{P}{V}\\\\I=\dfrac{3.5}{120}\\\\I=0.029\ A

So, the electric current is 0.029 A.

6 0
3 years ago
A bucket of water with mass 5 kg sits on the ground with a coefficient of static friction of 0.35. What is the maximum force of
allochka39001 [22]

Answer:

The force of static friction is 17.15 N

Explanation:

It is given that,

Mass of the bucket, m = 5 kg

The coefficient of static friction is, \mu=0.35

We need to find the maximum force of static friction. It is given by :

F=\mu mg

F=0.35\times 5\ kg\times 9.8\ m/s^2

F = 17.15 N

So, the force of static friction is 17.15 N. Hence, this is the required solution.

6 0
4 years ago
A ball is moving with velocity 5 m/s in a direction which makes an angle of 30° with horizontal (i.e. with positive x-direction)
klasskru [66]

Answer:

Explanation:

(a)

From the given information:

The initial velocity v_1 = 5 m/s

The direction of the angle θ = 30°

Therefore, the component along the x-axis = v_1 \ cos \ \theta

v_{1 \ x } = 5 \ cos \ 30^0

v_{1x} = 4.33 \ m/s

The component along the y-axis = v_2 { \ sin \  \theta}

v_{1 \ y } = 5 \ sin \ 30^0

v_{1 \ y } = 2.5 \ m/s

To find the final velocity( reflected velocity)

using the same magnitude v_2 = 5 \ m/s

The angle from the x-axis can be \theta_r = 90^0+60^0

= 150°

Thus, the component along the x-axis = v_2  \ cos \theta _r

v_{2x} = - 0.433 \ m/s

The component along the y-axis = v_2 \ sin \theta_r

v_{2y} = 5 \ sin \ 150^0

v_{2y} = 2.5 \ m/s

(b)

The velocity v_1 can be written as in vector form.

v_1 ^{\to}  = v_1 x \hat {i} + v_1 y \hat {j}

v_1 ^{\to}  =4.33 \ \hat {i} +  2.5 \  \hat {j}  ----  (1)

The reflected velocity in vector form can be computed as:

v_2 ^{\to}  = v_2 x \hat {i} + v_2 y \hat {j}

v_2 ^{\to}  =-4.33 \ \hat {i} +  2.5 \  \hat {j}  --- (2)

The change in velocity = v_2 ^{\to} - v_1 ^{\to}

\Delta v ^{\to} = - 4.33 \hat i + 2.5 \hat j - 4.33 \hat i - 2.5 \hat j

\Delta v ^{\to} = - 8.66 \hat  { i }

(c)

The magnitude of change in velocity = | \Delta V |

| \Delta V | = 8.66 m/s

6 0
3 years ago
What is the mean height for the grass used as a control?
motikmotik
The mean height for the grass used as a control is equal to the total number of the data came from the control grass divided by the number of control grass in the experiment. The mean height means the average height of the grass.
5 0
3 years ago
A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the bal
Snowcat [4.5K]

Answer:

78 N s

Explanation:

The impulse exerted on the ball is given by:

I = F \Delta t

where

F is the magnitude of the force

\Delta t is the duration of the collision

In this problem,

F = 39 N

\Delta t = 2 s

Substituting,

I=(39 N)(2 s)= 78 Ns

5 0
3 years ago
Other questions:
  • Be sure to answer all parts. Consider the following energy levels of a hypothetical atom: E4 −2.01 × 10−19 J E3 −5.71 × 10−19 J
    10·1 answer
  • how much force is needed to cause a 15 kilogram bike to accelerate at a rate of 10 meters per second?
    5·2 answers
  • Si se deja caer una piedra desde un helicóptero en reposo, entonces al cabo de 20 s cual será la rapidez y la distancia recorrid
    15·1 answer
  • A 2.00-kg object is attached to a spring and placed on a frictionless, horizontal surface. A horizontal force of 20.0N is requir
    11·1 answer
  • The magnitude of the centripetal force acting on an object traveling in a horizontal circular path will decrease and if the
    8·2 answers
  • Help with this physics task pls
    8·1 answer
  • The potential difference across a resistor in a particular electric circuit is 420 V. The current through the resistor is 19.0 A
    14·1 answer
  • Drake travel 1000m south and then 1200m west
    12·1 answer
  • The law of conservation of momentum states that (Help Asap!)
    5·1 answer
  • Prove that you can do a one foot spin.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!