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sleet_krkn [62]
2 years ago
11

Substrate: N-benzoyl-L-tyrosine ethyl ester (BTEE) 0.001M

Chemistry
1 answer:
Anna71 [15]2 years ago
7 0

Based on the dilution formula, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.

<h3>How can 50-fold dilution of the enzyme be done?</h3>

The 50-fold dilution of the stock enzyme solution can be done by using the dilution formula to determine the given volume of the stock solution required.

The dilution formula is given below:

  • C1V1 = C2V2

where:

  • C1 = Initial concentration of enzyme
  • C2 = Final concentration of enzyme
  • V1 = Initial volume
  • V2 = Final volume

From the given data for the enzyme dilution;

C1 = 1

C2 = 1/50 = 0.02

V1 = x

V2 = 5 ml

Making V1 subject of formula in the dilution formula:

V1 = C2V2/C1

V1 =  0.02 * 5/1 = 0.1 mL

Therefore, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.

Learn more about dilution at: brainly.com/question/24709069

#SPJ1

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Explanation:

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After you convert the volume from mL to L and the temperature from Celsius to Kelvin, you can use the equation to find the moles.

P = 760 mmHg                                      R = 62.36 L*mmHg/mol*K

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The molar mass represents the mass (g) of the gas per every 1 mole. Since you have been given a mass and mole value, you can set up a proportion to determine the molar mass.

\frac{?grams}{1 mole} =\frac{0.896grams}{0.0104moles}                                      <----- Proportion

?grams(0.0104moles) = 0.896                       <----- Cross-multiply

?grams = 86.2                                               <----- Divide both sides by 0.0104

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