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m_a_m_a [10]
3 years ago
14

A liquid at room temperature with high vapor pressure has:

Chemistry
1 answer:
Elanso [62]3 years ago
8 0
It’s B because of the quest
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1. 7.000 mmhg = ______ KPa?<br> 2. 10.00 kPa = ________atm?<br> 3. 15.00 kPa______mmHg?
Minchanka [31]
1 kPa = 7.5 mmHg so 7.0 mmHg / 7.5 mmHg x 1 kPa = .93 kPa

101.3 kPa = 1 atm so 10 kPa / 101.3 kPa x 1 atm = .0987 atm

1 kPa = 7.5 mmHg so 15 kPa x 7.5 mmHg / 1 kPa = 112.5 mmHg
7 0
3 years ago
Which of the following is true?
Umnica [9.8K]

Answer:

The answer should be D

Explanation:

because turning 1 mole of propane to grams means its still one mole of propane just in a different unit.

8 0
2 years ago
Simple cell?
poizon [28]

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4 0
3 years ago
As a change of state takes place, heat and temperature
Alexeev081 [22]

Answer:

c. stays the same, changes

Explanation:

temperature and heat go hand in hand, however while the change of state occurs, the temperature remains the same while the heat increases since the heat input is constant.

5 0
3 years ago
Calculate how many moles of nh3 form when each quantity of reactant completely reacts?
anygoal [31]

3.6 moles NH_{3} required when each quantity of reactant completely reacts.

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A reaction's product yield can be predicted using mole ratios, as can the amount of reactant required to produce a specific amount of result.

The balanced chemical equation is :

3N_{2} H_{4}(l) → 4NH_{3}(g) + N_{2}(g)

Given is = 2.6 mol N_{2} H_{4}

As we see, 3 moles of N_{2} H_{4} reacts with  4 moles of NH_{3}.

Therefore,

n( NH_{3}) = n(  N_{2} H_{4} ) × \frac{4}{3}

n( NH_{3}) = 2.6mol^{*} \frac{4mol}{3mol}

n( NH_{3}) = 3.6 moles.

Therefores, 3.6 moles NH_{3} required when each quantity of reactant completely reacts.

Learn more about moles here;

brainly.com/question/20486415

#SPJ4

6 0
2 years ago
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