There are two <em>true</em> statements:
- When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
- V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.
<h3>How to use composition between two function</h3>
Let be <em>f</em> and <em>g</em> two functions, there is a composition of <em>f</em> with respect to <em>g</em> when the domain of <em>f</em> is equal to the range of <em>g</em>. In this question, the <em>domain</em> variable of the function V(r) is replaced by substitution.
If we know that V(r) = (4/3) · π · r³ and r(t) = (1/4) · t², then the composite function is:
V(t) = (4/3) · π · [(1/4) · t²]³
V(t) = (4/3) · π · (1/64) · t⁶
V(t) = (1/48) · π · t⁶
There are two <em>true</em> statements:
- When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
- V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.
To learn on composition between functions: brainly.com/question/12007574
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the answer is the first one A
One number is 4
Another is 2 I hope this helped
Alaina has $28 in her account and wants to buy shoes worth $45
So $28-$45=$-17
Her account status will be $ - 17
Hope this helps
Answer:
70
Step-by-step explanation:
Apparently, you want the ratio of the weights:
(dino weight)/(car weight) = (2.8×10^5)/(4×10^3)
= (2.8/4)×10^(5-3) = 0.7×10^2 = 0.7×100
= 70
The heaviest dinosaur weighed about 70 times the weight of an average car.
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Your calculator can do arithmetic in scientific notation. So can any spreadsheet.
The applicable rule of exponents is ...
(10^a)/(10^b) = 10^(a-b)
