Explanation:
There are 5 kinematic equations, and 5 variables.
Each question will give you 3 variables and ask you to solve for a fourth.
To determine which equation to use, look at which variable is <em>not</em> included in the problem.
For example, if the question does not include time, then you need to use a kinematic equation that does not have t in it. That would be:
v² = v₀² + 2aΔx
Or, if the question does not include the final velocity, then you need a kinematic equation that does not have v in it. That would be:
Δx = v₀ t + ½ at²
Answer:
C
Explanation:
Most discussions of refraction will have a diagram similar to that of C.
The angle of incidence is measured from the normal to the boundary, as is the angle of refraction. The product of the sine of the angle and the index of refraction is the same for the media on either side of the boundary.
n₁·sin(θ₁) = n₂·sin(θ₂)
For media, such as optical fiber, that has an index of refraction greater than 1, the angle of refraction will be smaller in that media than the angle of incidence coming from air.
Figure C applies.
Answer:
The answer(s) for this question are as followed: A, C, & D
Explanation:
I hope this helped, let me know if i missed any.
Answer:
(I). The time at highest point 4.0 sec.
(II). It returns to back to its original height in 8.1 sec
Explanation:
Given that,
Velocity 
(I). We need to calculate the time at highest point
Using equation of motion
Where, v = final velocity
u = initial velocity
g = acceleration due to gravity
t = time
Put the value into the formula
(II). We know that, when the ball to travel from the initial point and reached at initial point then the displacement is zero.
We need to calculate the total time when it returns to back to its original height
Using equation of motion
Where, s = displacement
g = acceleration due to gravity
t = time
u = velocity
Put the value in the equation
Hence. (I). The time at highest point 4.0 sec.
(II). It returns to back to its original height in 8.1 sec
Entropy is randomness.
It mostly applies to gas particles because they move around randomly and freely
