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Mazyrski [523]
4 years ago
15

A night lamp uses a 30 W bulb. If it is left on continuously for 8 hours, how much energy will it use?

Physics
2 answers:
den301095 [7]4 years ago
6 0

Answer:

Explanation:

30W * 8 h = 240 Wh = 0.240 kWh

bezimeni [28]4 years ago
4 0

Answer:

0.24 kWh

Explanation:

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A basketball player jumps straight up with a speed of 14 m/s. How high did the player jump?
alexira [117]

Answer:

<em>The basketball player jumped 10 m high.</em>

Explanation:

<u>Vertical Launch Upwards </u>

In a vertical launch upwards, an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=\frac{v_o^2}{2g}

The basketball player jumps up with a speed of vo=14 m/s. The maximum height is:

\displaystyle h_m=\frac{14^2}{2*9.8}

\displaystyle h_m=\frac{196}{19.6}=10

The basketball player jumped 10 m high.

7 0
3 years ago
A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What
spin [16.1K]

Answer:

The  wavelength is \lambda_ 1 =  574.2 nm

Explanation:

From the question we are told that  

      The  thickness is t =  198 nm  =  198 *10^{-9 }\ m

      The refractive  index of the non-reflective coating is  n_m  =  1.45  

       The  refractive  index of glass is n_g  = 1.50

       

Generally the condition for  destructive  interference is mathematically represented as

            2 *  n_m *  t  *  cos (\theta) =  n  *  \lambda

Where \thata \theta is the angle of refraction which is  0° when the light is strongly transmitted

    and  n is the order maximum interference

        so  

             \lambda = \frac{2 *  n *  t  *  cos (\theta )}{n}

at the point n =  1  

           \lambda _1 = \frac{2 *  1.45  *  198*10^{-9}  *  cos (0 )}{1}

           \lambda_1  = 574.2 *10^{-9}

          \lambda_1  = 574.2 nm

at  n =2  

         \lambda _2  =  \frac{\lambda _1 }{2}

         \lambda _2  =  \frac{574.2*10^{-9} }{2}

         \lambda _2  =  2.87 1 *10^{-9} \ m

         \lambda _2  =  287. 1  nm

Now we know that the wavelength range of visible light is  between

           390 \ nm \to  700 \ nm

   So the wavelength of visible light that is been transmitted is  

          \lambda_ 1 =  574.2 nm

           

6 0
4 years ago
Kelsey the triathelete swims 1.5 km east, then bikes 40 km north, and then runs 10 km west. Which choice gives the
Fittoniya [83]

Answer:

Hey,. its a simple question. hope you learn from the solution. check attached picture

Explanation:

3 0
3 years ago
If the thermometer reads 20° Celsius, what's the temperature in Fahrenheit? A. 52° B. 68° C. 72° D. 36°
Eduardwww [97]
The answer is B. 68°
6 0
3 years ago
An astronaut holds a rock 100 m above surface of Planet X. The rock is then thrown upwards with a sleek of 15m/s. The rock reach
Gelneren [198K]

Answer:5 m/s^{2}

Explanation:

This problem is related to vertical motion, and the equation that models it is:

y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

Where:

y=0m is the rock's final height

y_{o}=100 m is the rock's initial height

V_{o}=15 m/s is the rock's initial velocity

\theta=90\° is the angle at which the rock was thrown (directly upwards)

t=10 s is the time

g is the acceleration due gravity in Planet X

Isolating g and taking into account sin(90\°)=1 :

g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t) (2)

g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s)) (3)

g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

5 0
3 years ago
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