-- find the horizontal and vertical components of F1.
-- find the horizontal and vertical components of F2.
-- find the horizontal and vertical components of F3.
-- add up the 3 horizontal components; their sum is the horizontal component of the resultant.
-- add up the 3 vertical components; their sum is the vertical component of the resultant.
-- the magnitude of the resultant is the square root of (vertical component^2 + horizontal component^2)
-- the direction of the resultant is the angle whose tangent is (vertical component/horizontal component), starting from the positive x-direction.
Answer:
a) 1.3 rad/s
b) 0.722 s
Explanation:
Given
Initial velocity, ω = 0 rad/s
Angular acceleration of the wheel, α = 1.8 rad/s²
using equations of angular motion, we have
θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²
where
θ2 - θ1 = 53.2 rad
t2 - t1 = 7s
substituting these in the equation, we have
θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²
53.2 =ω(0) * 7 + 1/2 * 1.8 * 7²
53.2 = 7.ω(0) + 1/2 * 1.8 * 49
53.2 = 7.ω(0) + 44.1
7.ω(0) = 53.2 - 44.1
ω(0) = 9.1 / 7
ω(0) = 1.3 rad/s
Using another of the equations of angular motion, we have
ω(0) = ω(i) + α*t1
1.3 = 0 + 1.8 * t1
1.3 = 1.8 * t1
t1 = 1.3/1.8
t1 = 0.722 s
Answer:
x = 2
Explanation:
if it was -7 = the square root of both 2x-9 together, it would be false.
if it was square root of just 2x in the equation, the answer is:
x = 2
°°°°°°°°°
-7 = √2x - 9
-√2x = -9 + 7
√-2x = -2
√2x = 2
2x = 4
x = 2
Answer:
The train's displacement is zero.
Explanation:
Given data,
The time taken by the train from NY to Washington and back is, t = 6 h 5 min
The distance between the two stations is, d = 363 km
Therefore, the total distance the train traveled is, d' = 726 km
The displacement is defined as the change in position coordinates with respect to its original position.
If the train travels from one point and returns back to the same point after some time, there is no change in the position coordinates with respect to its original position.
Hence, the train's displacement is zero.
Glass on glass,tire on concrete,tire on snow