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iragen [17]
2 years ago
14

Where do nebulae come from, in the opinion of science?

Physics
1 answer:
Mkey [24]2 years ago
7 0

Answer:

It formed from the same cloud of dust that our entire galaxy is made from

You might be interested in
2. El sonido de una ballena es en especial de frecuencia baja, pero existe una especie de ballena la Whalien cuya frecuencia es
ikadub [295]

Answer:

The sound of a whale is especially low frequency, but there is a species of whale the Whalien whose frequency is 52 Hz, if the propagation speed of the wave is 1400m / s What will be its period in the water and the air? And what will be the wavelength in each medium? Remember that the propagation speed in air is 340m / s

Explanation:

From wave equation, the speed, wavelength and frequency is related using

V = fλ

Where

V is the speed

f is the frequency

And λ is the wavelength

So,

The frequency of the whale is

f = 52Hz

The speed in water is V_w = 1400m/s

The speed in air is V_a = 340m/s

We want to find the period in each medium, the period is related to the frequency and since the frequency is constant.

Then, period in equal in both medium

T = 1 / f

T_w = T_a = 1 / f

T = 1 / 52

T = 0.0192 seconds

We want to find the wavelength in each medium

For water,

V = fλ

V_w = f × λ_w

Then,

λ_w = V_w / f.

λ_w = 1400 / 52 = 26.92 m

The wavelength in water is 26.92m

Now, in air

V = fλ

V_a = f × λ_a

Then,

λ_a = V_a / f.

λ_a = 340 / 52 = 6.54 m

The wavelength in air is 6.54 m

In Spanish

De la ecuación de onda, la velocidad, la longitud de onda y la frecuencia se relacionan usando

V = fλ

Dónde

V es la velocidad

f es la frecuencia

Y λ es la longitud de onda

Entonces,

La frecuencia de la ballena es

f = 52Hz

La velocidad en el agua es V_w = 1400m / s

La velocidad en el aire es V_a = 340m / s

Queremos encontrar el período en cada medio, el período está relacionado con la frecuencia y dado que la frecuencia es constante.

Luego, período igual en ambos medios

T = 1 / f

T_w = T_a = 1 / f

T = 1/52

T = 0.0192 segundos

Queremos encontrar la longitud de onda en cada medio

Para agua,

V = fλ

V_w = f × λ_w

Entonces,

λ_w = V_w / f.

λ_w = 1400/52 = 26,92 m

La longitud de onda en el agua es de 26,92 m.

Ahora en el aire

V = fλ

V_a = f × λ_a

Entonces,

λ_a = V_a / f.

λ_a = 340/52 = 6,54 m

La longitud de onda en el aire es de 6.54 m.

8 0
4 years ago
The common version of Newton’s second law of motion, EF= ma, is actually a special case that is true only when an objects _____
vladimir2022 [97]

Answer:

A

Explanation:

only is true when the objects mass is constant

6 0
3 years ago
Read 2 more answers
Is this object showing acceleration for the first 2 seconds? explain your answer.
iVinArrow [24]
Yes. The line is increasing. The flat line at the top of the graph is where there is not acceleration and the decreasing line is deceleration.
3 0
3 years ago
The freezing point of a solution prepared by dissolving 150 × 10–3 g of caffeine in 10.0 g of camphor is lower by 3.07°C than th
Finger [1]

Answer:

Molar Mass=193.9738 g/mol

Molar Mass≅194g/mol

Explanation:

Consider the formula:

m=ΔT/K_{f}

where:

ΔT is freezing point depression

K_{f} is freezing point depression constant

m is the morality=(moles of solute/kg of solvent)

Now:

m=\frac{3.07}{39.7}

m=0.07733 moles of solute/kg of solvent

Now:

0.07733 (moles of solute/kg of solvent) *0.010 kg of solvent

7.733*10^{-4} moles of solute(Caffeine)

Molar mass = Mass of solute/moles of solute

Molar Mass=\frac{150*10^-3}{7.733*10^{-4} }

Molar Mass=193.9738 g/mol

Molar Mass≅194g/mol

6 0
3 years ago
How much elastic potential energy does a spring store when it is compressed by 0.2 m if it has a spring constant of 5 N/m?​
dybincka [34]

0.1 J of elastic potential energy will be stored by the spring when it gets compressed by 0.2 m if it has the spring constant of 5 N/m.

Elastic potential energy can be defined as the potential energy stored by the spring when it is stretched or compressed.

  • Amount of energy stored in the elastic material or spring is directly proportional to the amount of compression or elongation.
  • It is represented by U.
  • Mathematically, U = \frac{1}{2} k x^{2} ; k is the spring constant and x is the compression or expansion suffered by the spring

According to the question.

Compression in the spring, x = 0.2 m

Spring constant, k = 5 n/m

Elastic potential Energy, U = \frac{1}{2} (0.2)^{2} (5)

U = 0.1 J

0.1 J of elastic potential energy will be stored by the spring.

To know more about elastic potential energy,

brainly.com/question/2611925

#SPJ1

3 0
1 year ago
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