All categories

3 years ago

Is this object showing acceleration for the first 2 seconds? explain your answer.

Physics

1 answer:

iVinArrow [24]3 years ago

3 0

Yes. The line is increasing. The flat line at the top of the graph is where there is not acceleration and the decreasing line is deceleration.

You might be interested in

When the sphere makes a complete revolution around its circular path, does it spend:_______

topjm [15]

Answer:

Explanation:

the same amount of time in both halves of the circle

5 0

2 years ago

Help me with this one aswell, too confused and tired for this

gogolik [260]

D all of the above applies to the functions of the nervous system.

7 0

2 years ago

Suppose you wish to fabricate a uniform wire out of 1.10 g of copper. If the wire is to have a resistance R = 0.390 Ω, and if al

Citrus2011 [14]

To solve this problem we will apply the concepts related to volume, as a function of length and area, as of mass and density. Later we will take the same concept of resistance and resistivity, equal to the length per unit area. Once obtained from the known constants it will be possible to obtain the area by matching the two equations:

Mass of copper wire $(m) = 1.10g = 1.10*10^{-3} kg$

Density $(\rho)= 8.92*10^3kg/m^3$

Resistively of copper $(\gamma) = 1.7*10^{-8}\Omega \cdot m$

Resistance (R) = 0.390\Omega

Volume is defined as,

$V= lA \text{ and }\frac{m}{\rho}$

$lA= \frac{1.10*10^{-3}}{8.92*10^3}$

$lA = 1.233*10^{-7} m^3$ (1)

We know that,

$\frac{l}{A} = \frac{R}{\gamma}$

$\frac{l}{A}= \frac{0.390\Omega}{1.7*10^{-8}\Omega m}$

$\frac{l}{A} = 2.2941*10^7 m^{-1}$ (2)

Multiplying equation we have

$l^2 = (1.233*10^{-7})( 2.2941*10^7)$

$l^2 = 2.8286m^2$

$l =\sqrt{2.8286m^2}$

$l = 1.68m$

Therefore the length of the wire is 1.68m

6 0

3 years ago

What causes glowsticks to give off light?

iren2701 [21]

Phenyl oxalate ester is responsible for the luminescence in aglow stick. The reaction with hydrogen peroxide causes the liquid inside a glow stick to glow

3 0

3 years ago

A flexible shaft consists of a 3 mm diameter steel wire in a flexible hollow tube which imposes a frictional torque of 0.04 N m

Rom4ik [11]

Answer:

2.5m

Explanation:

Torque is defined as the rotational effect of a force on a body.

The torque T for the maximum shear stress is given as 0.1 Nm

Frictional torque is the torque caused by a frictional force

The frictional torque F is given as 0.04 Nm/m

The maximum length of the shaft is thus given as

L = T / F

= 0.1/0.04

L= 2.5 m

6 0

3 years ago