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Alexus [3.1K]
3 years ago
10

The gravitational force between two objects is ______ proportional to the products of the masses and _______ proportional to the

square of the distance between them.
Physics
2 answers:
Rudiy273 years ago
6 0

directly, inversely ... newton's grav eqn

solmaris [256]3 years ago
3 0

Explanation:

The gravitational force between two objects is <u>directly</u> proportional to the products of the masses and <u>inversely</u> proportional to the square of the distance between them. It is known as Newton's law of gravitation.

In mathematical terms it is given by :

F=G\dfrac{Mm}{r^2}

Where

M and m are two masses

r is the distance between them

G = universal gravitational constant

The value of G is a universal constant. Its value do not varies from one location to another. G=6.67\times 10^{-11}\ m^3kg^{-1}s^{-2}    

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Law Incorporation [45]

Answer:

The force acting on a body is always equal to the product of the mass of the body and its acceleration.

Explanation:

The force of a body is defined as the product of mass and acceleration of the body.

According to Newton's second law, wherever there is a change in momentum of the body for an interval of time, there is a force acting on it.

                         F = (mv - mu) / t

                             = m (v -u) /t

                              = m a

Where,

                                 (v - u)/t - is the change in velocity of the body in the interval of time. It is equal to the acceleration of the body.

Hence, the equation for the force for any body becomes, F = m x a

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A reference point allows you to determine the _____________ of an object.
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Answer:

a reference point allows you to determine the motion of an object :)

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A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away
Tatiana [17]

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length,  the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

<h3>What is the electric field intensity 20cm away from the rod along its perpendicular bisector?</h3>

Generally, the equation for the  initial electric field intensity   is mathematically given as

dEp=\int{kd/r}cosd\theta

Therefore

e1=kd/r{sin\theta2+sinR1}

Hence

E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2

E1=B*9*10^{13})/(10*110)*\sqrt{2}

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In conclusion, the electric field intensity

E1=1.598*10^11v/m

Read more about Electric field

brainly.com/question/9383604

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