Answer:
A- Solubility decrease.
B- Solubility increase.
C- No solubility change.
Explanation:
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In this case, since the solubility of salt stands for the maximum amount of salt that can be added to a specific mass of water, usually 100 g; we need to take into account that for table salt in aqueous solution, the higher the temperature the larger the solubility and the lower the temperature the smaller the solubility; it means that more salt is dissolved in the same mass of water at higher temperatures and vice versa. Therefore, A- would decrease the solubility as the solution is cooled down and B- would increase the solubility as the solution is heated up.
Moreover, since the mass of water is assumed to remain the same, adding more salt do not affect the solubility but increase the degree of saturation of the solution up to supersaturated, yet the solubility remains unchanged.
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You will need 75.0ml grams of potassium cyanide
(2.5)(3.5)=10V²
The answer is 0.875 repeating liters.
Answer:
65.4%
Explanation:
The redox reaction is a 1:1:1 reaction because the reagents suffer a double displacement reaction, and the substance that is substituted have the same charge (H+ and Br-), thus, we first need to know which of the reagents is the limiting.
Let's test the 4-nitrobenzaldehyde as the limiting. The mass needed for sodium borohydride (m) is the mass given of 4-nitrobenzaldehyde multiplied by the stoichiometric mass of sodium borohydride divided by the stoichiometric mass of 4-nitrobenzaldehyde. The stoichiometric mass is the number of moles in the stoichiometric representation (1:1:1) multiplied by the molar mass, so:
m = (4.13 * 37.83*1)/(151.12*1)
m = 1.034 g
So, the mass needed of the other reagent is larger than the mass that was given, so, it will be the limiting, and the stoichiometric calculus must be done with it.
The mass of the product that was expected is then:
m = (0.700*153.14*1)/(37.83*1)
m = 2.83 g
The percent yield is the mass that was formed divided by the expected mass, and then multiplied by 100%:
%yield = (1.85/2.83)*100%
%yield = 65.4%
The one whose molar mass is smaller than sodium.
Fluorine is 19 g
Chlorine= 35.5 g
Bromine= 80 g
so in sodium fluoride, the percent of sodium is the largest.
