Answer:
23.5g of FeO
Explanation:
Hello,
The question above is asking us to find the mass of iron oxide produced from 15g of Fe and 8.5g of O. Well, to solve this question, we'll require the equation of reaction.
2Fe + O₂ → 2FeO
From the equation of reaction, 2 moles of Fe plus 1 mole of oxygen will produce 2 moles of FeO
Molar mass of Fe = 56g/mol
Molar mass of FeO = 72g/mol
Molar mass of O = 16 × 2 = 32g/mol
Number of moles = mass / molar mass
Mass = number of moles × molar mass
Mass of Fe = 2 × 56 = 112g
Mass of O = 32g
Mass of FeO = 2 × 72 = 144g
From the equation of reaction, (112 + 32)g (Fe + O2) reacts to produce 144g of FeO
114g of reacts produce 114g of FeO
15g of Fe + 8.5g of O2 = ?
(15 + 8.5)g (Fe + O2) = x
X = (23.5 × 114) / 114
x = 23.5g
Therefore, 15g of Fe and 8.5g of O2 will react to produce 23.5g of FeO
