Answer:
tetrahedral
As carbon has no 4 valence electrons that are occupied by 4 chlorine atoms, we get 0 lone pair in carbon and sp3 hybridisation which leads to tetrahedral shape.
Answer:
56.8 g
Explanation:
Your first conversion factor is the molar mass of H2O to convert from grams of water to moles. Your second conversion factor is the mole ratio of 2 mol C2H10 for every 10 mol H2O. Your last conversion factor is the molar mass of C2H10 to convert from moles back to grams.
150. g H2O • (1 mol H2O / 18.02 g H2O) • (2 mol C2H10 / 10 mol H2O) • (34.1 g C2H10 / 1 mol C2H10) = 56.8 g C2H10
It would be 4.6cgL not sure tho because I didint do that good in this
Water will have higher surface tension.
Explanation:
There are strong hydrogen bonds and strong intermolecular forces present in water. Water is polar in nature that is why surface tension is present in it. The force of attraction between the particles is the main factor for surface tension.
The cohesion force in the liquid causes surface tension.
Since the other substance is acetone which does not form strong intermolecular forces hence it has low value of surface tension. They have low cohesive forces and get stick to the surface and are spilled instead of attaining minimal volume.
Answer:
Explanation:
Cubic decimeter is the same unit as liter; so, mole per cubic decimeter is mole per liter, and that is the unit of concentration of molarity. Thus, what is asked is the molarity of the solution. This is how you find it.
1. <u>Take a basis</u>: 1 dm³ = 1 liter = 1,000 ml
2. <u>Calculate the mass of 1 lite</u>r (1,000 ml) of solution:
- density = mass / volume ⇒ mass = density × volume
Here, the density is given through the specific gravity
Scpecific gravity = density of acid / density of water
Take density of water as 1.00 g/ml.
- density of solution = 1.25 g/ml
- mass solution = 1.25 g/ml × 1,000 ml = 1,250 g
3. <u>Calculate the mass of solute</u> (pure acid)
- % m/m = (mass of solute / mass of solution) × 100
- 56 = mass of solute / 1,250 g × 100
- mass of solute = 56 × 1,250g / 100 = 700 g
4. <u>Calculate the number of moles of solute</u>:
- moles = mass in grams / molar mass = 700 g / 70 g/mol = 10 mol
5. <u>Calculate molarity (mol / dm³)</u>
- M = number of moles of solute / liter of solution = 10 mol / 1 liter = 10 mol/liter.