1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
arlik [135]
3 years ago
13

How much of a 1.00 mg sample of americium remains after 3 half-lives?

Chemistry
2 answers:
notka56 [123]3 years ago
5 0
Answer: 0.125mg americium

Half-lives is a set of duration when a sample will become half of their original mass. In this case, the initial mass is 1mg and the sample is going for 3 times half-lives. Then the calculation would be: 1mg 1/2^{3} = 1/8 mg= 0.125mg.
Sliva [168]3 years ago
3 0

A 1 mg sample of americium becomes \boxed{0.125{\text{ mg}}} after 3 half-lives.

Further Explanation:

The process in which an unstable nucleus releases energy in the form of different particles like alpha particles, beta particles, and gamma particles is termed as radioactivity.

Half-life

As is evident from its name, it is the time after which the amount of radioactive substances becomes half of its original amount. It is represented by  .

The expression to calculate the amount of substance is as follows:

{{\text{A}}_{\text{0}}} = {{\text{A}}_{\text{t}}}{\left( 2 \right)^{\text{n}}}                                                                               …… (1)

Here,

{{\text{A}}_{\text{t}}} is the final amount of substance.

{{\text{A}}_{\text{0}}} is the initial amount of substance.

n is the number of half-lives.

Rearrange equation (1) for {{\text{A}}_{\text{t}}}.

{{\text{A}}_{\text{t}}} = \left( {\dfrac{{\text{1}}}{{{{\left( 2 \right)}^{\text{n}}}}}} \right)\left( {{{\text{A}}_{\text{0}}}} \right)     …… (2)                                                                                

The value of {{\text{A}}_{\text{0}}} is 1 mg.

The value of n is 3.

Substitute 1 mg for {{\text{A}}_{\text{0}}} and 3 for n in equation (2) to calculate the amount of americium.

\begin{aligned}{{\text{A}}_{\text{t}}}&= \left( {\frac{{\text{1}}}{{{{\left( 2\right)}^{\text{3}}}}}} \right)\left( {{\text{1 mg}}} \right)\\&=\left( {\frac{1}{8}} \right)\left( {1{\text{ mg}}} \right)\\&= 0.125{\text{ mg}}\\\end{aligned}  

Therefore 0.125 mg of americium remains after 3 half-lives.

Learn more:

  1. Find the age of the fabric: brainly.com/question/8716136
  2. Which nuclear emission is negatively charged? brainly.com/question/2261727

Answer details:

Grade: Senior School

Chapter: Nuclear chemistry

Subject: Chemistry

Keywords: half-life, 1 mg, 0.125 mg, americium, n, 3 half-lives, radioactivity, unstable nucleus, t1/2, substance, initial amount, final amount, number of half-lives, alpha particles, beta particles, gamma particles, energy, half, amount of substance, original amount.

You might be interested in
PLSS HELP! The gas carbon dioxide is a pure substance. Which of the following is true about carbon dioxide? (4 points)
Nadusha1986 [10]

Answer:

The answer is option A..

5 0
2 years ago
Which is the balanced equation for:<br> Al2O3 + Fe – Fe3O4 + AL
Sloan [31]

Answer:

4Al203 + 9Fe -> 3Fe3O4 + 8Al

Amount of Al on reactant side: 8

Amount of Al on product side: 8

Amount of O on reactant side: 12

Amount of O on product side: 12

Amount of Fe on reactant side: 9

Amount of Fe on product side: 9

6 0
3 years ago
How many moles of chlorine gas and 120°C and 33.3 ATM would occupy a vessel of 12 L?
Mashutka [201]
<h3>Answer:</h3>

12.387 moles

<h3>Explanation:</h3>

We are given;

Temperature of chlorine, T = 120°C

But, K = °C + 273.15

Therefore, T = 393.15 K

Pressure, P = 33.3 Atm

Volume, V = 12 L

We are required to calculate the number of moles of chlorine gas,

To find the number of moles we are going to use the ideal gas equation;

PV = nRT

R is the ideal gas constant, 0.082057 L.atm/mol.K

Therefore, rearranging the formula;

n = PV÷RT

Hence;

n = (33.3 atm × 12 L) ÷ (0.082057 × 393.15 K)

  = 12.387 moles

Therefore, the number of moles of chlorine are 12.387 moles

8 0
3 years ago
Laura sees a horse pulling a buggy.
Tcecarenko [31]

Answer:

B

Explanation:

I think that the anserw is B.

4 0
2 years ago
Chlorofluorocarbons photodissociate to produce chlorine atoms, cl•, which have been implicated in decreasing the concentration o
GrogVix [38]

Answer:

The role that chlorine atoms have in increasing the depeltion rate ozone is that Cl acts as a catalyst.

Explanation:

  • From the two steps of the reaction:
  1. O₃ + Cl· → ClO· + O₂
  2. ClO· + O → Cl· + O₂
  • The overall reaction is: O₃ + O → 2O₂
  • It is clear that ClO· is an intermediate that has been produced within the first step and has been consumed in the second step.
  • Also, Cl· is considered as a catalyst in this reaction that it has been consumed in the first step and has been produced in the second step, which means that it does not get up in the reaction, that is the main characteristic of the catalyst.
  • The catalyst usually increases the rate of the reaction by lowering its energy of activation (The minimum energy that is required to initiate the reaction) by proceeding the reaction in an alternative pathway <em>(changing the reaction mechanism)</em>.
  • Hence, the role affecting the reaction rate that chlorine atoms have in increasing the depletion rate of ozone that it acts as a catalyst and does not get used up in the reaction.
8 0
2 years ago
Other questions:
  • The solubility of three compounds in water is shown in the table above. What best explains the observations shown in the table?
    8·2 answers
  • Explain why thermal and electrical conductivity is so high with copper
    11·1 answer
  • The reaction ch4 (g) + 2 o2 (g) ? co2 (g) + 2 h2o (g) is: the reaction ch4 (g) + 2 o2 (g) co2 (g) + 2 h2o (g) is: an exothermic
    10·1 answer
  • What is the unit for electric current.​
    12·1 answer
  • Is the sky actually blue?
    8·1 answer
  • which industrial city would have fewer air pollution incidents related to temperature inversions one on the great plains or one
    12·1 answer
  • How does the law of conservation of mass relate to the number of atoms of each element that are present before a reaction vs. th
    15·1 answer
  • .In a _____ relationship one variable increases and a second variable increases proportionally,
    13·1 answer
  • An object at a distance of 30 cm from a concave mirror gets its image at the same point. The focal length of the mirror is​
    6·1 answer
  • A student reads that sodium atoms (Na) react with chlorine (Cl2) molecules to form the compound sodium chloride (NaCl). Which mo
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!