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2 years ago

The base of the pyramid is a rectangle that is not a

1 answer:

7 0

An axis of symmetry passes through the vertex and is perpendicular to the base. Then the correct options are B, C, and E.

<h3>What is a rectangular pyramid?</h3>

Take a rectangle. This is the base. Now take 4 triangles such that each of them are connected to one-one side of the base rectangle and when they're taken together, they form a closed object. That shape is called rectangular pyramid.

The base of the pyramid is a rectangle that is not a square.

The pyramid has two planes of symmetry.

An axis of symmetry passes through the vertex and is perpendicular to the base.

An angle that measures 90° is an angle of rotation for an axis of symmetry for the pyramid.

Then the correct options are B, C, and E.

Learn more about rectangular pyramid here:

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an employee adds 160 fluid ounces of chemical to a feature that holds 120,000 gallons of water. did the employee add yhe correct

Hitman42 [59]

We are given a volume of 160 fluid ounces of chemical which is added to a container that holds 120,000 gallons of water. Assuming that the chemical has the same density as water, we just need to convert 120,000 gallons to ounces.

A conversion factor is taken from literature, 1 gallon is equivalent to 128 fluid ounces. So 160 fluid ounces is only 1.25 gallons, thus occupying minimal space in the container. The employee could add more of the chemical in the container. He can actually add 15360000 fluid ounces in total.

5 0

3 years ago

Help!!! ASAP pleaseee!!

Alla [95]

Answer:

1. The two numbers are 4 and 8.

Step-by-step explanation:

1) variables: x and y

2) x + y = 12, y - x = 4

3) graph using desmos or another graphing calculator

4) the solution is x = 4, y = 8, or 4 and 8. This means that 4 and 8 can be added to equal 12, and the difference between them is 4.

5 0

2 years ago

Luda [366]

Answer:

a) H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

b) $\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

c) $\chi^2_{crit}=5.991$

d) Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

High school Some College Bachelor or higher Total

Public Broadcasting 15 15 10 40

Commercial stations 5 25 10 40

Total 20 40 20 80

We need to conduct a chi square test in order to check the following hypothesis:

Part a

H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

The level os significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part b

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{20*40}{80}=10$

$E_{2} =\frac{40*40}{80}=20$

$E_{3} =\frac{20*40}{80}=10$

$E_{4} =\frac{20*40}{80}=10$

$E_{5} =\frac{40*40}{80}=20$

$E_{6} =\frac{20*40}{80}=10$

And the expected values are given by:

High school Some College Bachelor or higher Total

Public Broadcasting 10 20 10 40

Commercial stations 10 10 20 40

Total 20 30 30 80

Part b

And now we can calculate the statistic:

$\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(2-1)(3-1)=2$

Part c

In order to find the critical value we need to look on the right tail of the chi square distribution with 2 degrees of freedom a value that accumulates 0.05 of the area. And this value is $\chi^2_{crit}=5.991$

Part d

And we can calculate the p value given by:

$p_v = P(\chi^2_{3} >33.75)=2.23x10^{-7}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(33.75,2,TRUE)"

Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

7 0

3 years ago

Ax-bx+y=z the formula that could be used to find x

Illusion [34]

ax-bx+y=z the formula that could be used to find x

Answer:

5 0

3 years ago

Read 2 more answers

Urgent help... looks easy... just can't get it :(0.

r-ruslan [8.4K]

Answer: Choice D

-------------------------------------

Work Shown:

|2x - 6| < 4
-4 < 2x - 6 < 4
-4 + 6 < 2x - 6 + 6 < 4 + 6
2 < 2x < 10
2/2 < 2x/2 < 10/2
1 < x < 5

Plot open circles at x = 1 and x = 5 on the same number line
The shading will be in between the two open circles

That is why the answer is choice D

4 0

2 years ago