If an inhibitory synapse fires at the same time and at the same distance from the initial segment as an excitatory synapse of the same intensity there will be no changes in the potential in the firing zone.

Explanation:

Under normal conditions, the transmembrane potential depends on the ionic charges present in the intracellular and extracellular spaces. The extracellular space load is usually positive and in the cytoplasm is negative.

Depolarization occurs by opening ion channels that allow sodium to enter the cell, making the intracellular space more positive.
An opening of potassium channels releases this ion to the extracellular space, leading to hyperpolarization.

An excitatory synapse is one capable of depolarizing a cell and boosting the production of action potential, provided it is capable of reaching the threshold of said potential.

On the other hand, an inhibitory synapse is able to hyperpolarize the cell membrane and prevent an action potential from originating, so that they can inhibit the action of an excitatory synapse.

The interaction between two synapses, one excitatory and one inhibitory, -called synapse summation- will depend on the strength that each of them possesses. In this case, the intensity of both synapses being the same, there will be no changes in the membrane potential in the firing zone.

Learn more:

Excitatory and inhibitory postsynaptic potentials brainly.com/question/3521553

6 0

3 years ago

Then what would have happened to cell if it's nucleus was damaged or destroyed

solong [7]

The cell would be destroyed since the nucleus contains the chromosones and R.N.A.

7 0

3 years ago