Assuming Hardy-Weinberg equilbrium, we have
p + q = 1
where p = frequency of dominant allele and q = frequency of recessive allele. So
p = 1 - q = 1 - 0.04 = 0.96
Consequently we have
• p² = 0.9216 = frequency of hom ozygous domininant genotype
• pq = 0.0768 = frequency of heterozygous genotype
• q² = 0.0016 = frequency of hom ozygous recessive genotype
since
p² + 2pq + q² = 1
Waves that go up and down.. there's not pictures so explain more
During endocytosis the plasma membrane folds inwards either through phagocytosis for solits or pinocytosis for liquids.
During exocytosis vesicles for the inside of the cell fuse with the membrane and are released outside of the cell.
