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Elenna [48]
2 years ago
15

Describe how you would The list below shows the ages of all the presidents inaugurated in the twentieth century. Make a stem-and

-leaf plot to answer the question.
42, 51, 56, 55, 51, 54, 51, 60, 62, 43, 55, 56, 61, 52, 69, 64, 46, 54

In a stem-and-leaf plot of the data, how many leaves does stem 5 have?show the number 4 and 89 on a stem-and-leaf plot.
Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
7 0

The stem-and-leaf plots for both data set are shown in the attachment below.

Stem 5 would have 10 leaves.

<h3>How to Make a Stem-and-leaf Plot?</h3>

For example, if 23, 24, 25, 28 are data points in a data distribution, 2 would be represented as a stem while 3, 4, 5, 8 would be the leaf of the stem. The data would be represented on the stem-and-leaf plot as: 2 | 3, 4, 5, 8.

Given the data, 42, 51, 56, 55, 51, 54, 51, 60, 62, 43, 55, 56, 61, 52, 69, 64, 46, 54, the stem-and-leaf plot is shown in the image attached below.

Stem 5 would have 10 leaves, as shown in the stem-and-leaf plot attached below.

The numbers 4 and 89 are represented on the second stem-and-leaf plot in the attachment below.

Learn more about stem-and-leaf plot on:

brainly.com/question/8649311

#SPJ1

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"5 more than 3 times a number" translates to an equation is it true or false ?
lozanna [386]

Answer:

3n + 5

Step-by-step explanation:

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5 0
3 years ago
The sum of two numbers is 9.9, and the sum of the squares of the numbers is 53.21. What are the numbers?
Snezhnost [94]

Answer:

There are two possibilities:

x_{1} = 3.5 and y_{1} = 6.4

x_{2} = 6.4 and y_{2} = 3.5

Step-by-step explanation:

Mathematically speaking, the statement is equivalent to this 2-variable non-linear system:

x + y = 9.9

x^{2} + y^{2} = 53.21

First, x is cleared in the first equation:

x = 9.9 - y

Now, the variable is substituted in the second one:

(9.9-y)^{2} + y^{2} = 53.21

And some algebra is done in order to simplify the expression:

98.01-19.8\cdot y +2\cdot y^{2} = 53.21

2\cdot y^{2} -19.8\cdot y +44.8 = 0

Roots are found by means of the General Equation for Second-Order Polynomials:

y_{1} \approx \frac{32}{5} and y_{2} \approx \frac{7}{2}

There are two different values for x:

y = y_{1}

x_{1} = 9.9-6.4

x_{1} = 3.5

y = y_{2}

x_{2} = 9.9 - 3.5

x_{2} = 6.4

There are two possibilities:

x_{1} = 3.5 and y_{1} = 6.4

x_{2} = 6.4 and y_{2} = 3.5

5 0
3 years ago
A car with a cost price of $5200 is<br> sold at a profit of 15%. Calculate the<br> selling price
andriy [413]

Answer:

We are given the initial price of a car and we are also told that the car sold for a 15% profit which means that the price that the car was sold for is 15% more than it's initial price.  This is just a simple multiplication problem which we multiply the initial price by the total percentage plus 0.15

Sold\ Price = Initial\ Price *(Total\ Percentage+Profit\ Percentage)

Sold\ Price = \$5200*(1+0.15)

Sold\ Price = \$5200*(1.15)

Sold\ Price = \$5980

Therefore, our final answer is that the selling price was $5980

<u><em>Hope this helps! </em></u>

5 0
2 years ago
Help me find the area of the shaded region
dalvyx [7]
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7 0
4 years ago
Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by
Fudgin [204]

The given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

Given that, the expression can be written as.

(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)

By simplifying the above equation,

\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}

By taking out the common terms from the equation,

\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}

By simplifying the above equation by cancel out the common factors.

\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}

Now, by taking (-1) common from (-2c+1) we get,

\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}

By simplifying the above equation, we get the expression,

-3c

So the given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

7 0
3 years ago
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