Question

Can someone help me pls

Answer 1

Answer:

  (d)  x = (5±√53)/2

Step-by-step explanation:

The given quadratic equation is in standard form, so the coefficients are readily identified. The solution is given by the quadratic formula based on those coefficients.

Quadratic formula

The solution to the quadratic equation ax² +bx +c = 0 is given by the formula ...

  $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Application

The given equation has coefficients a = 1, b = -5, c = -7, so the solutions given by the formula are ...

  $x=\dfrac{-(-5)\pm\sqrt{(-5)^2-4(1)(-7)}}{2(1)}=\dfrac{5\pm\sqrt{25+28}}{2}\\\\\boxed{x=\dfrac{5\pm\sqrt{53}}{2}}$