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drek231 [11]
2 years ago
11

Can someone help me pls

Mathematics
1 answer:
irina [24]2 years ago
3 0

Answer:

  (d)  x = (5±√53)/2

Step-by-step explanation:

The given quadratic equation is in standard form, so the coefficients are readily identified. The solution is given by the quadratic formula based on those coefficients.

<h3>Quadratic formula</h3>

The solution to the quadratic equation ax² +bx +c = 0 is given by the formula ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

<h3>Application</h3>

The given equation has coefficients a = 1, b = -5, c = -7, so the solutions given by the formula are ...

  x=\dfrac{-(-5)\pm\sqrt{(-5)^2-4(1)(-7)}}{2(1)}=\dfrac{5\pm\sqrt{25+28}}{2}\\\\\boxed{x=\dfrac{5\pm\sqrt{53}}{2}}

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Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
3 years ago
You do not need to line up the decimal points when subtracting two decimal numbers.
marta [7]
Your answer is false. hope that helped
8 0
4 years ago
Read 2 more answers
Someone please help me it would mean alot !!
myrzilka [38]

Answer:

y intercept ( 0, 0.4)

x intercept ( 0.3, 0)

Step-by-step explanation:

The y intercept is where is crosses the y axis and the x value is zero

(0, 0.4)

The x intercept is where is crosses the x axis and the y value is zero

(0.3,0)

4 0
3 years ago
This is as far as I got can you check my work so far and tell me where to go from here
umka21 [38]
You did a simple mistake by forgetting to add 4 to itself in the square root. (-4^2=16)

x=(4 +/- sqrt(16-8))/4
x=(4 +/- sqrt(8))/4

Is this enough to get you started again?
8 0
3 years ago
Use this picture for all <br>Make sure 1-4 is correct<br>and the answer to 5
qwelly [4]
I can't answer cause u didn't show the angles
3 0
4 years ago
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