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oksano4ka [1.4K]
2 years ago
9

What must the charge (sign and magnitude) of a particle of mass 1.45 g be for it to remain stationary when placed in a downward-

directed electric field of magnitude 600 N/C ? Use 9.80 m/s2 for the magnitude of the free-fall acceleration.
Physics
1 answer:
sergey [27]2 years ago
8 0

q = -21 * 10^{-6} C

<h3>What is Free-fall acceleration?</h3>

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 m/s at sea level on the Earth.

As we know that charge and its sign that remains in equilibrium is under gravity must be such that it will balance the gravitational force by electric force,

mg =qE

1.45 * 10^{-3}(9.80)=q(600)\\\\q = 21 *10^{6} C\\\\

and its sign must be negative so that it will have upward electric force

so it is

q = -21 * 10^{-6} C

The charge of a particle of mass is -21 * 10^{-6} C

Learn more about Free-fall acceleration: brainly.com/question/2165771

#SPJ1

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Answer:

he formula for the gravitational force includes the gravitational constant, which has a value . The unit of the gravitational force is Newtons (N). Fg = gravitational force between two objects ( ) G = gravitational constant ( ) m1 = mass of the first object (kg)

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A long electric cable is suspended above the earth and carries a current of 345 A parallel to the surface of the earth. The eart
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Explanation:

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Where I = 345A is the current in the wire, B = 5.6*10^{-5} T is the magnetic magnitude generated by Earth. L = 46.9 m is the cable length. \theta = 88.2^o is the angle between vector B and cable direction.

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A wave has a wavelength of 10 mm and a frequency of 14 hertz. What is its speed?
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When the force acting on the body equal to acceleration?
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Consult Interactive Solution 10.37 to explore a model for solving this problem. A spring is compressed by 0.0647 m and is used t
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Answer:

\omega=32.14\ rad/s

Explanation:

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