Answer:
The force exerted by the rope is FT = 225.06 [N]
Explanation:
In order to solve this problem we must use a static analysis, since Globe does not move. For a better understanding in solving this problem, a free body diagram with the forces acting on the globe is attached.
The buoyant force acts upward as it causes the balloon to tend to float, the weight of the balloon tends to lower the balloon and the downward tension force does not allow the balloon to float
The buoyant force is defined by the following equation:
FB = Ro*V*g
where:
FB = Buoyant force [N]
Ro = density of the air = 1.3 [kg/m^3]
V = volume of the balloon = 20 [m^3]
g = gravity acceleration = 9.81 [m/s^2]
FB = 1.3*20*9.81 = 255.06 [N]
Now we do a sum of forces equal to zero in the y-axis
FB - 30 - FT = 0
255.06 -30 = FT
FT = 225.06 [N]
Answer:
Explanation:
a) Total distance traveled by the whale = 6.9 km + 1.8 km + 3.7 km = 12.4 km
b) the magnitude and the direction of the displacement of the whale = 6.9 km due east - 1.8 km due west = 5.1 due east
it final displacement = 5.1 km due east + 3.7 k due east = 8.8 km due east
c) average speed in km / hr = total distance traveled / total time = 12.4 km / 0.5 hr ( 30 min/ 60 min × 1 hr) = 24.8 km / hr
d) average velocity in km / h = total displacement / total time = 8.8 km / 0.5 h = 17.6 km/h
Answer:
The net force acting on the person is, F = 560 N
Explanation:
Given data,
The downward acceleration of the elevator, a = 1.8 m/s²
The weight of the person is, W = mg
= 686 N
Therefore the mass of the person,
m = W /g
= 686 / 9.8
= 70 kg
The net force acting on the person,
F = mg - ma
= 686 - 70 x 1.8
= 560 N
Hence, the net force acting on the person is, F = 560 N
Answer:
here is explanation
Explanation:
Proxima Centauri The closest star to our own Is still 40,208,000,000,000 km away.
(OR ABOUT 268,770 AU)
