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k0ka [10]
3 years ago
9

The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t , where the time tis in seconds. The

Physics
1 answer:
Reika [66]3 years ago
6 0

Complete question:

The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t³ , where the time tis in seconds. The

particle is momentarily at rest at t is:

Select one:

a. 9.3s

b. 1.3s

C. 0.75s

d.5.3s

e. 7.3s

​

Answer:

b. 1.3 s

Explanation:

Given;

position of the particle, x(t)=1 6t- 3.0t³

when the particle is at rest, the velocity is zero.

velocity = dx/dt

dx /dt = 16 - 9t²

16 - 9t² = 0

9t² = 16

t² = 16 /9

t = √(16 / 9)

t = 4/3

t = 1.3 s

Therefore, the particle is momentarily at rest at t = 1.3 s

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What is the mass of a child in a wagon that has a velocity of 10 m/s and a Momentum of 30 KG* M/S
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Explanation:

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3 years ago
4. A 1200 kg car traveling North at 20.0 m/s collides with a 1400 kg car traveling South at 22.0 m/s. The two
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Answer:-2.61 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_{o} must be equal to the final momentum p_{f}:

p_{o}=p_{f} (1)

Where:

p_{o}=mV_{o}+MU_{o} (2)

p_{f}=(m+M)V_{f} (3)

m=1200 kg is the mass of the first car

V_{o}=20 m/s is the velocity of the first car, to the North

M=1400 kg is the mass of the second car

U_{o}=-22 m/s is the mass of the second car, to the South

V_{f} is the final velocity of both cars after the collision

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Isolating V_{f}:

V_{f}=\frac{mV_{o}+MU_{o}}{m+M} (5)

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Finally:

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Answer:

the cost of operating the light bulb is 72 cents.

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Given;

cost of electricity, C = 6 cents / kW.h

power of light bulb, P = 100 W

time of light power consumption, t = 4 hours per day for 30 days

total time = 4 hours x 30 = 120 hours

Power consumed by the light bulb is calculated as;

P = 100 x 120 = 12000 w.h = 12 kW.h

Cost of power consumption = 6 cents/kWh x 12 kWh

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Therefore, the cost of operating the light bulb is 72 cents.

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