Electromagnetic radiation is an energy that is known as light. so electromagnetic radiation will have the same speed as the speed of light which is 3 x 10^8 m/s. so the distance it travel at 55 x 10^-6 s is:
D = ( 3 x 10^8 m/s ) ( 55 x 10^-6 s )
D = 16500 m
Answer:
increasing; speeding up is my answer
Answer:
The answer to your question is : 521.8 m
Explanation:
Data:
Different heights
Time first object (tfo) = 10.7 s
Time second object (tso)= 14.8 s
Initial speed of both objects(vo) = 0 m/s
a = 9.81 m/s²
Formula:
h = vot + 1/2 (a)(t)² but vo = 0 so, h = 1/2 (a)(t)²
Then, height fo h = 1/2 (9.81)(10.7)² = 561.6 m
height so h = 1/2(9,81)(14.8)² = 1074.4 m
Difference in their heights = 1074.4 m - 561.6 m = 521.8 m
Answer:
1. 218.55 N
2. 
3. 
Explanation:
Part 1;
Net force 
where m is mass, g is gravitational force and 
is the angle of inclination
Frictional force, 
is given by
where 
is the coefficient of static friction
Since 
, therefore, the block doesn’t slip and the frictional force acting is mgh=218.55N
Part 2.
Using the relationship that
Frictional force 
The maximum angle of inclination 
Part 3:
Net force on the object is given by
where 
is the coefficient of kinetic friction
= 9.8 ( sin 38 - (0.51) cos 38 )
= 
