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Akimi4 [234]
2 years ago
15

A proton has a positive electric charge of q = 1.6 × 10–19 coulombs. what is the electric potential at a point 5.3 × 10–11 m fro

m the proton? 4.4 × 10–18 volts 2.7 × 101 volts 3.0 × 10–9 volts 5.1 × 101 volts
Physics
1 answer:
Natalija [7]2 years ago
4 0

B. The electric potential at the given point from the proton is 2.7 x 10¹ volts

<h3>Electric potential of the proton</h3>

The electric potential of the proton is calculated as follows;

V = kq/r

where;

  • k is Coulomb's constant
  • q is charge
  • r is distance

V = (9 x 10⁹ x 1.6 x 10⁻¹⁹)/(5.3 x 10⁻¹¹)

V = 27.2 volts

V = 2.7 x 10¹ volts

Learn more about electric potential here: brainly.com/question/14306881

#SPJ1

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Milk with a density of 1020 kg/m3 is transported on a level road in a 9-m-long, 3-m-diameter cylindrical tanker. The tanker is c
jeka57 [31]

Solution :

Given data is :

Density of the milk in the tank, $\rho = 1020 \ kg/m^3$

Length of the tank, x = 9 m

Height of the tank, z = 3 m

Acceleration of the tank, $a_x = 2.5 \ m/s^2$

Therefore, the pressure difference between the two points is given by :

$P_2-P_1 = -\rho a_x x - \rho(g+a)z$

Since the tank is completely filled with milk, the vertical acceleration is $a_z = 0$

$P_2-P_1 = -\rho a_x x- \rho g z$

Therefore substituting, we get

$P_2-P_1=-(1020 \times 2.5 \times 7) - (1020 \times 9.81 \times 3)$

           $=-17850 - 30018.6$

           $=-47868.6 \ Pa$

           $=-47.868 \ kPa$

Therefore the maximum pressure difference in the tank is Δp = 47.87 kPa and is located at the bottom of the tank.

         

4 0
3 years ago
What is the acceleration of a car going 50 mph that slows down to rest over 10 seconds?
VladimirAG [237]

Answer:

If the velocity is constant, then there is no acceleration. That is, the value of the acceleration is 0.

Explanation:

6 0
3 years ago
suppose a car manufacturer tested its cars for front end collsion by hauling them up on a crane and dropping them from a certain
IRINA_888 [86]

Initial height: 66.5 m

Explanation:

The problem can be solved by using the principle of conservation of energy.

If we neglect air resistance, the total mechanical energy of the car is conserved during the fall, therefore we can write:

K_i + U_i = K_f + U_f

where :

K_i = 0 is the kinetic energy of the car at the top (it starts from rest)

U_i = mgh is the gravitational potential energy of the car at the top, with:

m = the mass of the car

g = the acceleration of gravity

h = the heigth of the car

K_f = \frac{1}{2}mv^2 is the kinetic energy of the car just before hitting the ground, with

v = 130 km/h final speed of the car

U_f = 0 is the gravitational potential energy of the car at the bottom

Re-arranging the equation,  we find

mgh=\frac{1}{2}mv^2

and we have:

g=9.8 m/s^2\\v = 130 km/h = 36.1 m/s

Solving for h, we find the initial height of the car:

h=\frac{v^2}{2g}=\frac{36.1^2}{2(9.8)}=66.5 m

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647  

brainly.com/question/10770261  

#LearnwithBrainly

5 0
3 years ago
a car going 22 m/s accelerates to pass a truck. Five seconds later the car is going 35 m/s. Calculate the acceleration of the ca
Maksim231197 [3]
Using the formula

a\: = \frac{v - u}{t}

a = \frac{35 m/s \: - \: 22 m/s}{5s}

a = 2.6 {m/s^2}
5 0
3 years ago
Fusion and fission are both processes that involve which fundamental force? to ask? A. gravitational B. weak nuclear C. electrom
marin [14]
Fusion & Fission are both processes that involve D. Strong Nuclear Fundamental forces
"D". is the answer
5 0
4 years ago
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