Question

Please answerASAP

Answer 1

Answer:

$8.9 m/s^2$

Explanation:

The period of a simple pendulum is given by the equation

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the lenght of the pendulum

g is the acceleration due to gravity at the location of the pendulum

We notice from the formula that the period of a pendulum does not depend on the mass of the system

In this problem:

-The pendulum comes back to the point of release exactly 2.4 seconds after the release. --> this means that the period of the pendulum is

T = 2.4 s

- The length of the pendulum is

L = 1.3 m

Re-arranging the equation for g, we can find the acceleration due to gravity on the planet:

$g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{2.4})^2(1.3)=8.9 m/s^2$