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alexgriva [62]
3 years ago
14

Swim ability is it materials ability to burn in the presence of

Chemistry
1 answer:
eduard3 years ago
6 0

Answer: Flammability is a material's ability to burn in the presence of oxygen.

Explanation: Chemical properties can be observed only when the substance changes into one or more different substances through chemical reactions or transformations. One of the chemical properties is flammability.

Flammability is a material's ability to burn in the presence of oxygen.

Remember, oxygen doesn't burn. Precisely flammable substances obtain substances that burn. Oxygen remains an oxidizing agent, which means it supports the combustion process. Oxygen causes other objects to catch fire at low temperatures and burns hotter and faster. But oxygen itself does not burn. Consequently, if you at present deliver fuel and fire, adding oxygen will provide the fire.

Carbon dioxide is the result of combustion. An example can be seen in firewood in a fireplace. One of the chemical properties of carbon-based wood is having the ability to burn. Chemically the wood turns into carbon dioxide when it burns and leaves a residue of ash. Furthermore, this ash residue cannot be turned back into the wood. Chemical changes result in new substances.

Consider an example of a combustion reaction to methane gas:

Our balanced equation for methane combustion implies that every one CH₄ molecule reacts with two O₂ molecules. The product of combustion is one carbon dioxide molecule and two steam or water vapor molecules.

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Misha Larkins [42]

Answer: Electrolyte Solutions

7 0
3 years ago
Convert 22 grams of copper Il chloride (Cucl2) to moles. <br>with work please ​
Fittoniya [83]
Hope this helps!

https://youtu.be/MT5tKijKZwQ
5 0
3 years ago
Read 2 more answers
What element is undergoing oxidation in the following reaction?. . CH4(g) +2O2 (g) -&gt; CO2(g) +2H2O(g). . . option . a) C. b)
SVETLANKA909090 [29]
The correct answer is a.) C. Oxidation occurs when an element loses electrons and increases its oxidation state. In the chemical equation, Carbon in CH4 has an oxidation state of 4- while Carbon in CO2 has an oxidation of 4+.
4 0
3 years ago
Read 2 more answers
To gain an idea as to how many atoms are in a gram or so of copper, use the larger balance
anygoal [31]

Answer:

Explanation:

To solve this problem, we must understand the relationship between mass of a substance and the number of atoms.

Atoms are the smallest indivisible particles of any matter. A substance can be made up of several number of atoms in their space.

The mass of any substance is a function of the amount of atoms its contains.

The mass of a substance is related in chemistry to the amount of atoms its contains using the parameter called the number of moles.

A mole is the amount of substance that contains the Avogadro's number of particles. This number is 6.02  x 10²³ particles. The particles here can be protons, neutrons, electrons, atoms e.t.c.

Now,

             Number of moles  = \frac{mass}{molar mass}

          Molar mass of copper  = 63.6g/mole

         Number of moles  = \frac{2}{63.6}  = 0.03mole

Since 1 mole of a substance contains  6.02  x 10²³atoms

        0.03 mole of copper will contain 0.03 x  6.02  x 10²³atoms

                                                    = 1.89 x 10²² atoms

He needs to add 1.89 x 10²² atoms to make 2g of the sample.

7 0
3 years ago
One photon of a certain type of light has an energy of 7.32x10^-19 J. a.) What is the frequency of this type of light? b.) What
iren [92.7K]

Answer:

f = 1.1041 × 10¹⁵ s⁻¹

λ = 2.72  × 10⁻⁷ m

Explanation:

Given data:

Energy of photon = 7.32 × 10⁻¹⁹ J

Wavelength = ?

Frequency = ?

Solution:

Formula

E = h. f

h = planck's constant = 6.63 × 10⁻³⁴ Kg.m²/s

Now we will put the values in equation

f = E/h

Kg.m²/s² = j

f = 7.32 × 10⁻¹⁹ Kg.m²/s² / 6.63 × 10⁻³⁴ Kg.m²/s

f = 1.1041 × 10¹⁵ s⁻¹

Wavelength of photon.

E = h.c /λ

λ =  h. c / E

λ = (6.63 × 10⁻³⁴ Kg.m²/s × 3 × 10⁸ m/s) / 7.32 × 10⁻¹⁹ Kg.m²/s²

λ = 19.89 × 10⁻²⁶ / 7.32 × 10⁻¹⁹ m

λ = 2.72  × 10⁻⁷ m

7 0
3 years ago
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