Answer:
They are both listed under group 11 on the periodic table and both are highly conductive of electricity
Explanation:
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D) energy required to remove a valence electron
Explanation:
The ionization energy is the energy required to remove a valence electron from an element.
Different kinds of atoms bind their valence electrons with different amount of energy.
- To remove the electrons, energy must be supplied to the atom.
- The amount of energy required to remove the an electron in the valence shell is the ionization energy or ionization potential.
- The first ionization energy is the energy needed to remove the most loosely bound electron in an atom in the ground state.
- The ionization energy measures the readiness of an atom to loose electrons.
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Ionization energy brainly.com/question/5880605
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I always thought it was a mixture but can also be a compound
The term that describes when a solvent is holding as much solute in solution as it is able for a given temperature is called supersaturated solution. A little disturbance to this solution some of the solute will crystallize or precipitate out since this solution is not stable.
The boiling point of water at 1 atm is 100 degrees celsius. However, when water is added with another substance the boiling point of it rises than when it is still a pure solvent. This called boiling point elevation, a colligative property. The equation for the boiling point elevation is expressed as the product of the ebullioscopic constant (0.52 degrees celsius / m) for water), the vant hoff factor and the concentration of solute (in terms of molality).
ΔT(CaCl2) = i x K x m = 3 x 0.52 x 0.25 = 0.39 °C
<span> ΔT(Sucrose) = 1 x 0.52 x 0.75 = 0.39 </span>°C<span>
</span><span> ΔT(Ethylene glycol) = 1 x 0.52 x 1 = 0.52 </span>°C<span>
</span><span> ΔT(CaCl2) = 3 x 0.52 x 0.50 = 0.78 </span>°C<span>
</span><span> ΔT(NaCl) = 2 x 0.52 x 0.25 = 0.26 </span>°C<span>
</span>
Thus, from the calculated values, we see that 0.75 mol sucrose dissolved on 1 kg water has the same boiling point with 0.25 mol CaCl2 dissolved in 1 kg water.
