6.11.4 Test(TST): Circles Without Coordinates). The questions are in the document.
1 answer:
The value of AOB and BOC based in the information given in the circle will be 53°.
<h3>How to calculate the values in the circle?</h3>From the information given, the central angle is the angle that the vertex is at the center of the circle.
It was stated that OB bisects AOC. Therefore, since AOB is 53°, BOC is also 53°.
The value of AOC will now be:
= AOB + BOC
= 53° + 53°
= 106°
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Answer:
y = -5x - 3
Step-by-step explanation:
To answer this the slope must be clculated first
slope equation:
these variables symbolize ordered pairs, and the best part is that you can use any two ordered pairs for this example we can use (-5, 10) and (-3,0)
we'll call the first ordered pair 1 so x1 = -5 and y1 = 10.
the next odered pair is 2 so x2 = -3 and y2 = 0.
With this information layed out we can solve:
0 - 10 = -10
-3 - (-5) = 2 --- remember negatives cancel each other out to make a positive
= -5
the slope of the line is -5. Now the next thing to note is that one of the ordered pair (-3,0) is a y intercept. It's time to introduce the equatione of a line:
y = mx+b
There are other equations that can be used for a line but with the info given this equation best suits the data.
m = slope
y and x = are the ordered pair you can input into the equation to slove
b = the y intercept
So the equation would be:
y = -5x - 3