6.11.4 Test(TST): Circles Without Coordinates). The questions are in the document.
1 answer:
The value of AOB and BOC based in the information given in the circle will be 53°.
<h3>How to calculate the values in the circle?</h3>From the information given, the central angle is the angle that the vertex is at the center of the circle.
It was stated that OB bisects AOC. Therefore, since AOB is 53°, BOC is also 53°.
The value of AOC will now be:
= AOB + BOC
= 53° + 53°
= 106°
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Answer:
The correct option is;
Yes, the line should be perpendicular to one of the rectangular faces
Step-by-step explanation:
The given information are;
A triangular prism lying on a rectangular base and a line drawn along the slant height
A perpendicular bisector should therefore be perpendicular with reference to the base of the triangular prism such that the cross section will be congruent to the triangular faces
Therefore Marco is correct and the correct option is yes, the line should be perpendicular to one of the rectangular faces (the face the prism is lying on).
Answer:
cscθ =
Step-by-step explanation:
cscθ =
For a unit circle, radius = 1
hence, hypotenuse = 1
opposite = y
cscθ =
