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tamaranim1 [39]
1 year ago
10

Which is the correct equilibrium constant expression for the following reaction? 2brcl 3 (g) br 2 (g) 3cl 2 (g)

Chemistry
1 answer:
marishachu [46]1 year ago
6 0

Kc = concentrations of product / concentrations of reactant

Kc = [Br₂] [Cl₂]₃ / [BrCl₃]₂

What is the equilibrium constant?

The relationship between a reaction's products and reactants with regard to a certain unit is expressed by the equilibrium constant(K) This article introduces the mathematics needed to determine the partial pressure equilibrium constant as well as how to formulate expressions for equilibrium constants. By allowing a single reaction to reach equilibrium and then measuring the concentrations of each chemical participating in that reaction, one can determine the numerical value of an equilibrium constant. it is the ratio of product concentrations to reactant concentrations. The equilibrium constant for a given reaction is unaffected by the initial concentrations because the concentrations are measured at equilibrium.

To learn more about the equilibrium constant, visit:

brainly.com/question/19340344

#SPJ4

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6 0
4 years ago
Read 2 more answers
3. The molar volume of a gas at STP occupies<br> 0 1 kilopascal<br> O ooc<br> 12 grams<br> 22.4 L
Reil [10]

The molar volume of a gas at STP occupies <u>22.4 L.</u>

Option D

<u>Explanation:</u>

To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,

P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)

STP = 1 atm of pressure and 273 K for temperature

P = 1 atm

V = ?

n = 1 mole

R = 0.0821 atm L/mol K

T = 273 K

Using the equation,

\mathrm{PV}=\mathrm{nRT}

V=\frac{n R T}{P}

By substituting the above values, in the equation,

V=\frac{1 \times 0.082 \times 273}{1}=22.38\ L

V = 22.38 L

8 0
3 years ago
What is an empirical formula for a compound that is 82.2% nitrogen and 17.8% hydrogen
makkiz [27]
Percent to mass
Mass to mole
Divide by small
Multiply 'til whole

Assume 100 g of substance, then 82.2 g N and 17.8 g H.

82.2 g N * (1 mol/14.01 g N) = 5.86 mol N
17.8 g H * (1 mol/1.01 g H) = 17.6 mol H

Divide by the smallest mole
17.6 H / 17.6  = 1 H
5.86 N / 17.6 =  1/3 N

Multiply to make whole number ( x3 in this case)
3 x 1 H = 3H
3 x 1/3 N = 1 N

NH3
8 0
3 years ago
Distance divided by time
son4ous [18]
150÷3=50

350÷4=87.5

(50+87.5)÷2

137.5÷2

=68.75
4 0
3 years ago
No clue what do to do so help please lol
Julli [10]
I don’t know what the answer is just need points sorry
8 0
3 years ago
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