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The molar volume of a gas at STP occupies <u>22.4 L.</u>
Option D
<u>Explanation:</u>
To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,
P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)
STP = 1 atm of pressure and 273 K for temperature
P = 1 atm
V = ?
n = 1 mole
R = 0.0821 atm L/mol K
T = 273 K
Using the equation,


By substituting the above values, in the equation,

V = 22.38 L
Percent to mass
Mass to mole
Divide by small
Multiply 'til whole
Assume 100 g of substance, then 82.2 g N and 17.8 g H.
82.2 g N * (1 mol/14.01 g N) = 5.86 mol N
17.8 g H * (1 mol/1.01 g H) = 17.6 mol H
Divide by the smallest mole
17.6 H / 17.6 = 1 H
5.86 N / 17.6 = 1/3 N
Multiply to make whole number ( x3 in this case)
3 x 1 H = 3H
3 x 1/3 N = 1 N
NH3
150÷3=50
350÷4=87.5
(50+87.5)÷2
137.5÷2
=68.75
I don’t know what the answer is just need points sorry