Answer:
Percent yield = 84.5 %
Explanation:
Given data:
Mass of methanol = 229 g
Actual yield of water = 219 g
Percent yield of water = ?
Solution:
Chemical equation:
2CH₃OH + 3O₂ → 2CO₂ + 4H₂O
Number of moles of methanol:
Number of moles = mass/ molar mass
Number of moles = 229 g/ 32 g/mol
Number of moles = 7.2 mol
Now we will compare the moles of water with methanol.
CH₃OH : H₂O
2 : 4
7.2 : 4/2×7.2 = 14.4 mol
Mass of water:
Mass = number of moles × molae mass
Mass = 14.4 mol × 18 g/mol
Mass = 259.2 g
Percent yield:
Percent yield = actual yield / theoretical yield × 100
Percent yield = 219 g / 259.2 g × 100
Percent yield = 84.5 %
Answer:
Hydrogen is usually classified as a group 1 element since it has one valence electron, just like group 1 metals.
Explanation:
Answer:
1.126 M
Explanation:
From the question given, we obtained the following:
Mass of LiBr = 98g
Volume = 1 L
Molarity of LiBr =?
Next, we'll determine the number of mole of LiBr. This is illustrated below:
Molar Mass of LiBr = 7 + 80 = 87g/mol
Mass of LiBr = 98g
Number of mole = Mass/Molar Mass
Number of mole of LiBr = 98/87
Number of mole of LiBr = 1.126 mole
Now, we can calculate the molarity of LiBr. This is illustrated below:
Molarity is defined as mole per unit litre of the solution. Mathematically, it is represented as:
Molarity = mole /Volume
Mole of LiBr = 1.126 mole
Volume = 1 L
Molarity of LiBr =?
Molarity of LiBr = 1.126 mole /1 L
Molarity of LiBr = 1.126 M
A deep-sea diver must descend and ascend in short steps to equalize pressure on his body.