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3 years ago

6

In the triangle shown below, what is the approximate value of x?

2 answers:

mamaluj [8]3 years ago

8 0

Answer:

24.25 units for a.pe.x if the triangle has the sides x,14, and 28

Step-by-step explanation:

Verdich [7]3 years ago

3 0

Answer:

the answer the answer is the answer is C

Step-by-step explanation:

21 Unity

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What is the measure of ∠H? <br>1. 115<br>2. 65<br>3. 50<br>4. 25

ddd [48]

Answer:

2

Step-by-step explanation:

Since FG is congruent to FH, angles FGH and FHG are congruent since angles opposite congruent sides in a triangle are congruent.

3 0

2 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

A fair coin is flipped 5 times

wolverine [178]

Answer:

2/5

Step-by-step explanation:

The answer is common sense.

4 0

3 years ago

Please help ill give brainiest

vaieri [72.5K]

Answer:

give it

Step-by-step explanation:

the answer is m=1/4

8 0

3 years ago

Read 2 more answers

What is the inverse of g? <br> g(x) = 3/x+7

ikadub [295]

Given function :-

$\bf \implies g(x) = \dfrac{3}{x}+7$

To find its reverse , substitute y = g(x) .

$\bf \implies y = \dfrac{3}{x}+7$

Interchange x and y .

$\bf \implies x = \dfrac{3}{y}+7$

Solve for y .

$\bf\implies \dfrac{3}{y}= x -7 \\\\\bf\implies y =\dfrac{3}{x-7}$

Replace y with f-¹(x) .

$\implies\boxed{\red{\bf f^{-1}(x) = \dfrac{3}{x-7} }}$

6 0

3 years ago