Consider the baby being weighed in Figure 4.25.
1 answer:
The mass and tension due to the system are as follows:
- The mass of the child and scale = 10.6 kg
- The tension T, in the cord attaching the child to the scale = 104N
- The tension T', in the cord attaching the scale to the ceiling T' = 108.9 N
Tension is a type of pulling force due transmitted by means of a string or cable.
<h3>Force = mass * acceleration due to gravity</h3>a) The mass of the child and scale = 104/9.81 = 10.6 kg
b) The tension T, in the cord attaching the child to the scale = scale reading = 104N
c) The tension T', in the cord attaching the scale to the ceiling = scale reading + weight of scale
T' = 104 + (0.5 * 9.81)
T' = 108.9 N
d) The sketch is attached in the picture
In conclusion, the tension is force exerted on the cord due to the weight of the scale and the baby.
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Answer:
The centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².
Explanation:
The centripetal acceleration is given by:
Where:
: is the tangential speed = 9.50 m/s
r: is the distance = 6.00 m
Hence, the centripetal acceleration is:
Therefore, the centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².
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Answer:
T=26.03 N
Explanation:
Given that
Distance between poles = 12 m
Mass of block m= 4 kg
Sag distance = 5 m
Lets take tension in the clothesline is T.
The component of tension in vertical direction will be T cosθ.
By force balancing
2 T cosθ = 40
here
θ=39.80°
2 T cos39.8 = 40
T=26.03 N
