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MA_775_DIABLO [31]
2 years ago
14

Consider the baby being weighed in Figure 4.25.

Physics
1 answer:
Lunna [17]2 years ago
4 0

The mass and tension due to the system are as follows:

  • The mass of the child and scale = 10.6 kg
  • The tension T, in the cord attaching the child to the scale = 104N
  • The tension T', in the cord attaching the scale to the ceiling T' = 108.9 N

<h3>What is tension?</h3>

Tension is a type of pulling force due transmitted by means of a string or cable.

<h3>Force = mass * acceleration due to gravity</h3>

a) The mass of the child and scale = 104/9.81 = 10.6 kg

b) The tension T, in the cord attaching the child to the scale = scale reading = 104N

c) The tension T', in the cord attaching the scale to the ceiling = scale reading + weight of scale

T' = 104 + (0.5 * 9.81)

T' = 108.9 N

d) The sketch is attached in the picture

In conclusion, the tension is force exerted on the cord due to the weight of the scale and the baby.

Learn more about tension force at: brainly.com/question/24994188

#SPJ1

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Answer:

6.41 s

Explanation:

Under constant acceleration we know that

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The proof of used equation is given in the attachment.

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An airplane is traveling from North Africa to England. Which arrow correctly shows the direction gravity pulls the plane?
solniwko [45]

Given that,

The attached figure shows an airplane is traveling from North Africa to England.

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The arrow that shows the direction gravity pulls the plane.

Solution,

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If =12a andthe distance from each wire to point p is 0.12m, then what is the magnitude of the magnetic force per unit length on
vaieri [72.5K]

The magnitude of the magnetic force per unit length on the top wire is

2×10⁻⁵  N/m

<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>

To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula

F= \frac{\mu_0 I_f}{2\pi d}

Here we are given,

\mu_0= magnetic permeability

= 4\pi×10⁻⁷ H m⁻¹

If= 12 A

d= distance from each wire to point.

=0.12m

Now we put the known values in the above equation, we get

F= \frac{\mu_0 I_f}{2\pi d}

Or, F = \frac{4\pi \times 10^{-7}\times  12}{2\pi \times 0.12}

Or, F= 2×10⁻⁵ N/m.

From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.

Learn more about magnetic force:

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