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iogann1982 [59]
2 years ago
7

If a ball is thrown from a tall building, how tall is the building if it takes 6s for the ball to land?

Physics
1 answer:
daser333 [38]2 years ago
4 0

Answer:

the answer is 352.8m

Explanation:

Since the gravitational constant is denoted as g

g = 9.8  \:  \frac{m}{ {s}^{2} }

and the ball needed 6 seconds to land, so we can calculate the height of the building as:

h = 9.8  \:  \frac{m}{ {s}^{2} } \times {(6s)}^{2}  = 9.8  \:  \frac{m}{ {s}^{2} }  \times 36 {s}^{2}  = 352.8m

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If two objects are moving at the same speed, and Object 1 has four times as much mass as Object 2, how much momentum does Object
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The conservation of momentum is most closely related to
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<h2>B) Newton's 2nd law</h2>

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How should the student use the data collected and the known quantities from the experiment to determine the initial total mechan
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<h3>Method of using the data collected.</h3>

From the complete information, the student wants to use the data collected and the known quantities from the experiment to determine the initial total mechanical energy of the block-ramp-Earth system for all trials in the experiment.

In this case, it's important to use K = 1/2mv² with the block's initial speed for one trial due to the fact that the initial speed is the same in all the trials.

Learn more about experiments on:

brainly.com/question/17274244

7 0
2 years ago
5.00 kg of liquid water is heated to 100.0 °C in a closed system. At this temperature, the density of liquid water is 958 kg/m3.
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Answer:

1.04\times 10^7\ J.

Explanation:

In the question given :

Pressure is constant

Therefore, Work done, W=P\times\Delta V

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Final volume, V_f=8.50\ m^3.

Initial volume, V_i=\dfrac{Mass}{density}=\dfrac{5}{958}=5.22\times10^-3\ m^3.

Therefore, W=8.58\times 10^{5}\ J.

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Hence, this is the required solution.

8 0
3 years ago
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