If a ball is thrown from a tall building, how tall is the building if it takes 6s for the ball to land?

Physics

1 answer:

daser333 [38]2 years ago

4 0

Answer:

the answer is 352.8m

Explanation:

Since the gravitational constant is denoted as g

$g = 9.8 \: \frac{m}{ {s}^{2} }$

and the ball needed 6 seconds to land, so we can calculate the height of the building as:

$h = 9.8 \: \frac{m}{ {s}^{2} } \times {(6s)}^{2} = 9.8 \: \frac{m}{ {s}^{2} } \times 36 {s}^{2} = 352.8m$

You might be interested in

A(n) _______ is a point level measuring system consisting of a circuit of two or more probes or electrodes, or an electrode and

Digiron [165]

Answer:

Conductivity probe

Explanation:

The Conductivity Probe consists of two electrodes(also referred to as probes)or an electrode and a wall vessel where the material in the vessel completes the circuit as the level rises in the vessel.

It is used in measuring solution conductivity or total ionic concentration of aqueous samples.

6 0

2 years ago

A ship's wheel has a moment of inertia of 0.930 kilogram·meters squared. The inner radius of the ring is 26 centimeters, and the

Vikki [24]

We can use the formula of the moment of inertia given by:

$r\cdot F=I\alpha$

Where:

r = Distance from the point about which the torque is being measured to the point where the force is applied

F = Force

I = Moment of inertia

α = Angular acceleration

So:

$\begin{gathered} r\cdot F=(-0.26\times314+290\times0.32)=92.8-81.64=11.16 \\ I=0.930 \\ so,_{\text{ }}solve_{\text{ }}for_{\text{ }}\alpha: \\ \alpha=\frac{r\cdot F}{I} \\ \alpha=\frac{11.16}{0.930} \\ \alpha=\frac{12rad}{s^2} \end{gathered}$

Answer:

12 rad/s²

8 0

10 months ago

A boy is whirling a stone around his head by means of a string. The string makes one complete revolution every second; and the m

Damm [24]

Answer

given,

Tension of string is F

velocity is increased and the radius is not changed.

the string makes two complete revolutions every second

consider the centrifugal force acting on the stone