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iogann1982 [59]
2 years ago
7

If a ball is thrown from a tall building, how tall is the building if it takes 6s for the ball to land?

Physics
1 answer:
daser333 [38]2 years ago
4 0

Answer:

the answer is 352.8m

Explanation:

Since the gravitational constant is denoted as g

g = 9.8  \:  \frac{m}{ {s}^{2} }

and the ball needed 6 seconds to land, so we can calculate the height of the building as:

h = 9.8  \:  \frac{m}{ {s}^{2} } \times {(6s)}^{2}  = 9.8  \:  \frac{m}{ {s}^{2} }  \times 36 {s}^{2}  = 352.8m

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A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 57.3 c
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Answer with Explanation:

We are given that

Diameter of pipe,d_1=0.573 m

v_1=13.5 m/s

v_2=5.83 m/s

Volume flow rate of the petroleum along the pipe=Q_{refinery}=A_1v_1=v_(\frac{\pi d^2_1}{4})

Q_{refinery}=13.5\times (\pi\times \frac{0.573)^2}{4})=3.48 m^3/s

By equation of continuity

A_1v_1=A_2v_2

\frac{\pi d^2_1}{4}v_1=\frac{\pi d^2_2}{4}v_2

d^2_2=\frac{v_1}{v_2}d^2_1

d_2=\sqrt{\frac{v_1}{v_2}}d_1

d_2=0.573\sqrt{\frac{13.5}{5.83}}

d_2=0.87 m

d_2=0.87\time 100=87 cm

1 m=100 cm

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