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2 years ago

If a ball is thrown from a tall building, how tall is the building if it takes 6s for the ball to land?

Physics

1 answer:

daser333 [38]2 years ago

4 0

Answer:

the answer is 352.8m

Explanation:

Since the gravitational constant is denoted as g

$g = 9.8 \: \frac{m}{ {s}^{2} }$

and the ball needed 6 seconds to land, so we can calculate the height of the building as:

$h = 9.8 \: \frac{m}{ {s}^{2} } \times {(6s)}^{2} = 9.8 \: \frac{m}{ {s}^{2} } \times 36 {s}^{2} = 352.8m$

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An emu moving with constant acceleration covers the distance between two points that are 92 m

nasty-shy [4]

Answer:

a) $V_{o}=14.30 m/s$

b) $a=-0.046 m/s^{2}$

Explanation:

The complete question is written below:

An emu moving with constant acceleration covers the distance between two points that are 92 m apart in 6.5s. Its speed as it passes the second point is 14 m/s. What are (a) its speed at the first point and (b) its acceleration?

Since we are talking about constant acceleration, we can use the following equations:

$d=x-x_{o}=(\frac{V_{o}-V}{2})t$ (1)

$V=V_{o}+at$ (2)

Where:

$d=92 m$ is the distance between the two points

$V_{o}$ is the velocity of the emu at the first point

$V=14 m/s$ is the velocity of the emu at the second point

$t=6.5 s$ is the time it takes to the emu to cover the distance $d$

$a$ is the emu's constant acceleration

Knowing this, let's begin with the answers:

<h2>a) Speed at the first point</h2>

In this situation wi will use equation (1):

$d=(\frac{V_{o}-V}{2})t$ (1)

Finding $V_{o}$ :

$V_{o}=\frac{2d}{t}-V$ (3)

$V_{o}=\frac{2(92 m)}{6.5 s}-14 m/s$ (4)

$V_{o}=14.30 m/s$ (5)

<h2>b) Emu's acceleration</h2>

Now we will substitute (5) in equation (2):

$14 m/s=14.30 m/s+a(6.5 s)$ (6)

Finding $a$ :

$a=-0.046 m/s^{2}$ (7) This means the emu is decreasing its speed at a constant rate.

8 0

3 years ago

How will the equation of morion for an object moving with an ununifor motion change????? please help me !!!!!!

babymother [125]

Answer:

The equation of motion is derived based on the Newton’s laws of motion. And it changes accordingly when an object changes with uniform velocity.

Given is that object moves with uniform velocity, that is no change in velocity so there will no acceleration.

As we know

Here, u = v (due to uniform velocity)

1st equation of motion is, v = u + at

2nd equation of motion,

3rd equation of motion,

Explanation:

4 0

3 years ago

Why do astronomers find it difficult to detect individual exoplanets?

Maurinko [17]

Light from the stars, because the orbits make it difficult to see them.

6 0

3 years ago

Read 2 more answers

The Moon orbits Earth in an average of p = 27.3 days at an average distance of a =384,000 kilometers. Using Newton’s version of

Korvikt [17]

Answer:

The mass of the earth, $M=6.023\times 10^{24}\ kg$

Explanation:

It is given that,

Time taken by the moon to orbit the earth, $T=27.3\ days=2358720\ m$

Distance between moon and the earth, $r=384000\ km=384\times 10^6\ m$

We need to find the mass of the Earth using Kepler's third law of motion as :

$T^2=\dfrac{4\pi^2}{GM}r^3$

$M=\dfrac{4\pi^2r^3}{T^2G}$

$M=\dfrac{4\pi^2\times (384\times 10^6)^3}{(2358720)^2\times 6.67\times 10^{-11}}$

$M=6.023\times 10^{24}\ kg$

So, the mass of the earth is $6.023\times 10^{24}\ kg$ . Hence, this is the required solution.

7 0

3 years ago

A school bus moves slower and slower. Using what you have learned about forces, explain why the bus moves slower and slower.

MariettaO [177]

Explanation:

the weight of the people inside the bus

4 0

3 years ago