Answer:
x= 5.6
Step-by-step explanation:
we will need to put the information we currently have into an equation:
10•2•x= 112
then multiply 10•2 which equals 20...then the equation wil turn out like this:
20•x=112
now you will isolate the x... but how?? dividing 20 by itslef.. cancelling it out, and if you do one thing to the other side of the equation, you have to do it to the other...
20/20•x=112/20
you will end up with x= 122/20
you can use a calculator for this step, but to practice long division... (check the screen shot thingie)
hope this helped !! ^^
Answer:
One such situation is the amount of money in excess you paid for an item and the amount of change you will get. Another such scenario would be the total numbers of hours with respect to the total number of days. With more days, there will be more time hence more hours.
Step-by-step explanation:
Answer:
9
Step-by-step explanation:
3 times the sum of 4 and 2 = 3*(4+2)
= 3 * 6
= 18
18 - 9 = 9
![\bf \textit{Logarithm Cancellation Rules} \\\\ \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{log_a a^x = x}\qquad \qquad a^{log_a x}=x~\hfill\stackrel{recall}{ln=log_e}\qquad log_e(e^z)=z \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7BLogarithm%20Cancellation%20Rules%7D%20%5C%5C%5C%5C%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bwe%27ll%20use%20this%20one%7D%7D%7B%5Cdownarrow%20%7D%7D%7Blog_a%20a%5Ex%20%3D%20x%7D%5Cqquad%20%5Cqquad%20a%5E%7Blog_a%20x%7D%3Dx~%5Chfill%5Cstackrel%7Brecall%7D%7Bln%3Dlog_e%7D%5Cqquad%20log_e%28e%5Ez%29%3Dz%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%20)

and you plug that in your calculator to get about -0.27465307216702742285.