What elements are formed by stars having a mass greater than eight suns?
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Answer:
1533.6 kg NO
Explanation:
The reaction that takes place is:
- 4NH₃ + 5O₂ → 4NO + 6H₂O
First we <u>convert the masses of ammonia (NH₃) and oxygen gas (O₂) into moles</u>, using<em> their respective molar masses</em>:
- NH₃ ⇒ 869 kg ÷ 17 kg/kmol = 51.12 kmol NH₃
- O₂ ⇒ 2480 kg ÷ 32 kg/kmol = 77.5 kmol O₂
77.5 kmol of O₂ would react completely with (77.5 kmol O₂ * ) 62 kmol of NH₃. There are not as many kmol of NH₃, so NH₃ is the limiting reactant.
Now we <u>calculate how many kmol of NO are produced</u>, using the <em>limiting reactant moles</em>:
- 51.12 kmol NH₃ *
= 51.12 kmol NO
Finally we <u>convert kmol of NO to mass</u>, using its<em> molar mass</em>:
- 51.12 kmol NO * 30 kg/kmol = 1533.6 kg NO