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Inga [223]
3 years ago
8

What elements are formed by stars having a mass greater than eight suns?

Chemistry
1 answer:
Hoochie [10]3 years ago
5 0
An elements like helium and Boron are formed by stars having a mass of one to eight suns. The example elements that are formed by stars having a mass of one to eight suns are helium and boron. The stars normally turns into a white dwarf when the mass of the stars are less than 5 times the mass of the sun.
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Both 1,2−dihydronaphthalene and 1,4−dihydronaphthalene may be selectively hydrogenated to 1,2,3,4−tetrahydronaphthalene. One of
pochemuha

Answer:

1,4-dihydro = 113 kJ·mol⁻¹

1,2-dihydro = 101 kJ·mol⁻¹

Explanation:

In 1,4-dihydronaphthalene, the 2,3-double bond is isolated from the benzene ring.

In 1,2-dihydronaphthalene, the 3,4-double bond is conjugated with the benzene ring.

Thus, 1,2-dihydronaphthalene is partially stabilized by resonance interactions between the ring and the double bond (think, styrene).

1,2-Dihydronaphthalene is at a lower energy level because of this stabilization.

The heat of hydrogenation of 1,2-dihydronaphthalene is therefore less than that of the 1,4-isomer when each is hydrogenated to the common product, 1,2,3,4-tetrahydronaphthalene.

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3 years ago
Which answer below correctly the type of change and explanation for the separation of the iron with sulfur?
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3 years ago
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Answer:

the atoms of the original substances gain, lose and even share their very own electrons. write the symbols of the elements that form the compound. Write down the valency, and lastly go over valencies. This is all I got so far. I hope this helps

Explanation:

8 0
3 years ago
If your car gets 30.3 mi/gal, how many gallons of gasoline would you use if you drove 506.3 miles? 1 mile = 5280 ft (exactly) In
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Explanation:

Given: The car can drive 30.3 miles when 1 gallon of gasoline is used.

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Thus the amount of gasoline used is 16.7 gallons.


4 0
3 years ago
Read 2 more answers
Borane (BH3) adds to alkenes to form an alkylborane. In the first box draw the mechanism arrows, and in the second box draw the
OLEGan [10]

Answer:

The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.

Explanation:

The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.

6 0
3 years ago
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