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AysviL [449]
2 years ago
13

What is the pH range for an acid? 0-7 7-14 7 0

Chemistry
2 answers:
olga nikolaevna [1]2 years ago
7 0
<h3>Answer: Choice A)  0-7</h3>

Explanation:

If the pH is between 0 and 7, then we have an acid.

If the pH is between 7 and 14, then we have an alkaline base.

If pH = 7, then it's neutral.

Alik [6]2 years ago
6 0

Answer:

0-7

Explanation:

  • Any substance that has a pH of less than 7 is acidic - 0 is a strong acid whereas 6 is a weak acid.
  • A pH of 7 means that the substance is neutral.
  • Anything above pH 7 is alkaline, pH 8 is a weak alkaline and pH 14 is a strong alkaline.

Hope this helps!

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What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?
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Answer:

\% diss = 50\%

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}

Thus, it is possible to find x given the pH as shown below:

x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M

So that we can calculate the initial concentration of the acid:

\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\

[HA]_0=3.64x10^{-5}M

Therefore, the percent dissociation turns out to be:

\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%

Best regards!

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