All categories

3 years ago

1) How many moles are in 4.0x10^24 atoms?

Chemistry

1 answer:

-Dominant- [34]3 years ago

3 0

Answer:

<h2>6.64 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{4 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 6.644518...$

We have the final answer as

<h3>6.64 moles</h3>

Hope this helps you

You might be interested in

How many moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100.0 kPa and a temperature of 100.0 degrees Cel

o-na [289]

1.137448506 mol moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100.0 kPa and a temperature of 100.0 degrees Celsius.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas. The terms are: p = pressure, in pascals (Pa). V = volume, in $m^3$ .

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

PV= nRT

Given data:

P=100.0 kPa =0.986923 atm

T=100 degree celcius= 100 + 273 =373 K

V=35.5 L

Substituting the values in the equation.

n= $\frac{\;0,98 \;atm \;X \;35,5 \;L }{\;0,082\;atm / \;K mol \;X \;373 K}$

n= 1.137448506 mol

Hence, 1.137448506 mol moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100.0 kPa and a temperature of 100.0 degrees Celsius.

Learn more about ideal gas here:

brainly.com/question/16552394

#SPJ1

7 0

1 year ago

Select the electron-domain geometry for a molecule with three bonding domains and one nonbonding domain.

mamaluj [8]

Answer: C) Tetrahedral

Explanation:

The number of electron pairs is 4 that means the hybridization will be $sp^3$ but as there are three bonding domains and one nonbonding domain, thus electronic geometry is tetrahedral and the molecular geometry will be trigonal pyramidal.

Linear electron geometry is possible when number of electron pairs is 2 and the hybridization will be $sp^2$ .

Trigonal planar geometry is possible when number of electron pairs is 3 and the hybridization will be $sp^3$ .

Trigonal bipyramidal geometry is possible when number of electron pairs is 5 and the hybridization will be $sp^3d$ .

Octahedral geometry is possible when number of electron pairs is 6 and the hybridization will be $sp^3d^2$ .

6 0

3 years ago

What is the only planet in our solar system that rotates in a different direction from the other planets??

aksik [14]

Venus so that the sun rises in the west

4 0

2 years ago

Scientists believe that ancient bacteria represents the first evidence of life on Earth. Which of these best describes the proce

almond37 [142]

It's is reproduction in single called organisms

5 0

2 years ago

Read 2 more answers

if the mass of 191 grams NaCl reacted with 74 frams of calcium hydroxide and 80 grams of sodium hydroxide is produced, what mass

nadya68 [22]

<h3>Answer:</h3>

110.98 g/mol

<h3>Explanation:</h3>

The reaction between NaCl and Ca(OH)₂ is given by the equation;

2NaCl(aq) + Ca(OH)₂(s) → 2NaOH(aq) + CaCl₂(aq)

We are required to determine the mass of CaCl₂ produced,

We will use the following simple steps;

Step 1: Moles of NaCl and Ca(OH)₂ given

Number of moles = Mass ÷ Molar mass

Moles of NaCl

Mass of NaCl = 191 g

Molar mass NaCl = 58.44 g/mol

Number of moles = 191 g ÷ 58.44 g/mol

= 3.268 moles

= 3.27 Moles

Moles of Ca(OH)₂

Mass of Ca(OH)₂ = 74 g

Molar mass of Ca(OH)₂ = 74.093 g/mol

Number of moles = 74 g ÷ 74.093 g/mol

= 0.998 mole

= 1.0 mole

However, from the equation 2 moles of NaCl requires 1 mole of Ca(OH)₂

Therefore, from the amount of reactants available NaCl was in excess and Ca(OH)₂ is the limiting reactant .

Step 2: Moles of CaCl₂ produced

From the equation

1 mole of Ca(OH)₂ reacts with NaCl to produce 1 mole of CaCl₂

Therefore; the mole ratio of Ca(OH)₂ to CaCl₂ is 1: 1

Thus;

Moles of CaCl₂ produced is 1.0 moles

Step 3: Mass of CaCl₂ produced

Moles of CaCl₂ = 1.0 mole

Molar mass CaCl₂ = 110.98 g/mol

But; mass = number of moles × Molar mass

Therefore;

Mass of CaCl₂ = 1.0 mole × 110.98 g/mol

= 110.98 g CaCl₂

3 0

2 years ago