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creativ13 [48]
3 years ago
6

1) How many moles are in 4.0x10^24 atoms?

Chemistry
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

<h2>6.64 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{4 \times  {10}^{24} }{6.02 \times  {10}^{23} }   \\  = 6.644518...

We have the final answer as

<h3>6.64 moles</h3>

Hope this helps you

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3 years ago
Ethyl iodide (C2H5I) decomposes at a certain temperature in the gas phase as follows: C2H5I(g) → C2H4(g) + HI(g) From the follow
lutik1710 [3]

Answer:

Zero order

Explanation:

Looking at the data we can note a linear dependence between concentration and time.  

Time   Conc.

0          2

15         1.82

30        1.64

48        1.42

75        1.10

In the first 15 min it was consumed 2-1.82=0.18. So the rate is r=\frac{\Delta C}{\Delta t} = \frac{0.18}{15}=0.012

From 15 to 30 min (it has passed 15 min) is consumed 1.82-1.64=0.18, so as in the previous calculation the rate is r=0.012.

From 30 to 48  (it has passed 18 min)the rate is r= \frac{0.22}{18}\approx 0.012  

From 48 to 75  (it has passed 27 min) the rate is r= \frac{0.32}{27}\approx 0.012  

So these results suggest that despite of the ever minor concentration of the reactant the rate is ever the same. Hence the reaction rate could be expressed as r= k^{0} = 0.012 mol L^{-1} min^{-1} that is, the reaction is the zero order respect to C2H5I since it is not depending on concentration of C2H5I.  

7 0
3 years ago
What is the change in temperature in a 128g sample of titanium if it absorbs 2808J of heat energy at a temperature of 2°C? The s
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Given:

128g sample of titanium

2808J of heat energy

specific heat of titanium is 0.523 J/ g °C.

Required:

Change in temperature

Solution:

This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

Plugging in the values into the equation

H = mCpT

2808J = (128g) (0.523 J /g °C) T

T = 41.9 °C

3 0
3 years ago
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