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neonofarm [45]
3 years ago
9

Based on solubility, boiling point, and spectroscopic results, a chemist identified an unknown compound as an alcohol. Yet when

she tried to confirm this conclusion using a chromic acid test, she got a negative result. All of her results were correct. How is that possible? Briefly explain.
Chemistry
1 answer:
mojhsa [17]3 years ago
4 0

Answer:

The compound was a 3° alcohol.

Explanation:

The chromic acid test is positive for 1° and 2° alcohols, but negative for 3° alcohols.

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Provide 3 examples of substances that are mixtures and list the substances in them
Vedmedyk [2.9K]

Answer:

Water and salt = salt water

Oxygen and water = sea foam

Smoke and fog = smog

Explanation:

Hope this helped, nya~ :3

3 0
3 years ago
Read 2 more answers
A mixture of water and graphite is heated to 600 K in a 1 L container. When the system comes to equilibrium it contains 0.17 mol
Kryger [21]

Answer:

0.44 moles

Explanation:

Given that :

A mixture of water and graphite is heated to 600 K in a 1 L container. When the system comes to equilibrium it contains 0.17 mol of H2, 0.17 mol of CO, 0.74 mol of H2O, and some graphite.

The equilibrium constant K_c=  \dfrac{[CO][H_2]}{[H_2O]}

The equilibrium constant  K_c=  \dfrac{(0.17 )(0.17)}{0.74}

The equilibrium constant K_c=  0.03905

Some O2 is added to the system and a spark is applied so that the H2 reacts completely with the O2.

The equation for the reaction is :

H_2 + \dfrac{1}{2}O_2 \to H_2O \\ \\ 0.17 \ \ \ \ \  \ \ \ \ \to0.17

Total mole of water now = 0.74+0.17

Total mole of water now = 0.91 moles

Again:

K_c=  \dfrac{[CO][H_2]}{[H_2O]}

0.03905 =  \dfrac{[0.17+x][x]}{[0.91 -x]}

0.03905(0.91 -x) = (0.17 +x)(x)

0.0355355 - 0.03905x = 0.17x + x²

0.0355355 +0.13095 x -x²

x² - 0.13095 x - 0.0355355 = 0

By using quadratic formula

x = 0.265  or   x = -0.134

Going by the value with the positive integer; x = 0.265 moles

Total moles of CO in the flask when the system returns to equilibrium is :

= 0.17 + x

= 0.17 + 0.265

= 0.435 moles

=0.44 moles (to two significant figures)

3 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this li
Anastasy [175]

Answer:

-179.06 kJ

Explanation:

Let's consider the following balanced reaction.

HCl(g) + NaOH(s) ⟶ NaCl(s) + H₂O(l)

We can calculate the standard enthalpy change for the reaction (ΔH°r) using the following expression.

ΔH°r = 1 mol × ΔH°f(NaCl(s)) + 1 mol × ΔH°f(H₂O(l)) - 1 mol × ΔH°f(HCl(g)) - 1 mol × ΔH°f(NaOH(s))

ΔH°r = 1 mol × (-411.15 kJ/mol) + 1 mol × (-285.83 kJ/mol) - 1 mol × (-92.31 kJ/mol) - 1 mol × (-425.61 kJ/mol)

ΔH°r = -179.06 kJ

7 0
3 years ago
Represent the formation of cations for the following metal atoms using electron dot structures. (a) Al (b) Sr (c) Ba​
vagabundo [1.1K]

the formation of cations by using electron dot structures are :

a) Al

.

Al .    losing the three valence electrons makes the Al³⁺

.

b) Sr :  

  Sr :  losing the two valence electrons makes Sr²⁺

c) Ba

: Ba , losing the two valence electrons makes it Ba²⁺

A Lewis electron dot diagram is a representation of the valence electrons of an atom that employments specks around the image of the element. The number of dots equals the number of valence electrons within the molecule. These dots are arranged to the right and left and over and underneath the symbol, with no more than two dots on a side. Cations are the positive ions shaped by the loss of one or more electrons. The foremost commonly shaped cations of the representative elements are those that include the loss of all of the valence electrons.

To know more about the lewis electron dot diagram refer to the link brainly.com/question/14191114?referrer=searchResults.

#SPJ9

3 0
1 year ago
What is the purpose of a unit conversion?
Nataly [62]

<em><u>Unit conversion is very important because the rest of the world other than three contries uses the metric system. So, converting unitsis important in science because it uses the metric system. The metric system aremeasurements like cm, m, l, mL, etc.</u></em>

8 0
3 years ago
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