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neonofarm [45]
3 years ago
9

Based on solubility, boiling point, and spectroscopic results, a chemist identified an unknown compound as an alcohol. Yet when

she tried to confirm this conclusion using a chromic acid test, she got a negative result. All of her results were correct. How is that possible? Briefly explain.
Chemistry
1 answer:
mojhsa [17]3 years ago
4 0

Answer:

The compound was a 3° alcohol.

Explanation:

The chromic acid test is positive for 1° and 2° alcohols, but negative for 3° alcohols.

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Calculate the molarity of an hcl solution if a 10.00 ml sample requires 25.24 ml of a 1.600 m naoh solution to be neutralized.
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Answer:

The molarity of the HCl solution should be 4.04 M

Explanation:

<u>Step 1:</u> Data given

volume of HCl solution = 10.00 mL = 0.01 L

volume of a 1.6 M NaOH solution = 25.24 mL = 0.02524 L

<u>Step 2:</u> The balanced equation

HCl + NaOH → NaCL + H2O

Step 3: Calculate molarity of HCl

n1*C1*V1 = n2*C2*V2

Since the mole ratio for HCl and NaOH is 1:1 we can just write:

C1*V1 =C2*V2

⇒ with C1 : the molarity of HCl = TO BE DETERMINED

⇒ with V1 = the volume og HCl = 10 mL = 0.01 L

⇒ with C2 = The molarity of NaOH = 1.6 M

⇒ with V2 = volume of NaOH = 25.24 mL = 0.02524 L

C1 * 0.01 = 1.6 * 0.02524

C1 = (1.6*0.02524)/0.01

C1 = 4.04M

The molarity of the HCl solution should be 4.04 M

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