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11Alexandr11 [23.1K]
3 years ago
9

A chemist wishes to decrease the vapor pressure of a large volume of water. Which amount of solute will decrease it the most? (N

ote: Assume each sample of solute completely dissolves in the water.)
A)0.10 mol Al2(SO4)3

B)0.10 mol sucrose

C)0.40 mol glucose

D)0.20 mol NaCl
Chemistry
2 answers:
Vladimir79 [104]3 years ago
8 0

Answer: A) 0.10 mol Al_2(SO_4)_3

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

\frac{p^o-p_s}{p^o}=i\times x_2

where,

\frac{p^o-p_s}{p^o}= relative lowering in vapor pressure

i = Van'T Hoff factor  

x_2 = mole fraction of solute

1. For 0.10 mol Al_2(SO_{4})_3

Al_2(SO_4)_3\rightarrow 2Al^{3+}+3SO_4^{2-}  

, i= 5 as it is a electrolyte and dissociate to give 5 ions. and concentration of ions will be 2\times 0.1+3\times 0.1=0.5

2.  For 0.10 mol sucrose

, i= 1 as it is a non electrolyte and does not dissociate, concentration of ions will be 1\times 0.1=0.1

3. For 0.40 mol glucose

, i= 1 as it is a non electrolyte and does not dissociate,  concentration of ions will be 1\times 0.4=0.4

4. For 0.2 NaCl

NaCl\rightarrow Na^{+}+Cl^{-}  

, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be 1\times 0.2+1\times 0.2=0.4

Thus as concentration of solute is highest for Al_2(SO_4)_3 , the vapor pressure will be lowest.

valentinak56 [21]3 years ago
5 0

Answer:c

Explanation:

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