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3 years ago

White sugar and iodized salt did the resulting look same throughout?

Chemistry

1 answer:

Nonamiya [84]3 years ago

7 0

<h3>yes the look same after mixing them together.</h3>

Because White sugar settles at the bottom of iodized salt. White sugar completely mixed with iodized salt.

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Indicate the type of solute-solvent interaction that should be most important in each of the following solutions.a. LiCl in wate

topjm [15]

Explanation:

a. LiCl is an ionic molecule whereas water is a polar molecule with net dipole moment in it. There LiCl in water would have an ion-dipole force of interaction.

b. Both NF3 and CH3CN have dipole moment in them, since both are polar molecule. Hence, there would be dipole-dipole interaction.

c. Here both CCl4 and benzene are non polar molecules therefore, they have London dispersion force of interaction.

d. In methylamine and water both have hydrogen bonding in them. The nitrogen of CH3NH2 forms hydrogen bond with water.

5 0

3 years ago

How many moles are equal to 12.65 grams of Al2(SO4)3?

____ [38]

Answer:

0.03697 mol Al₂(SO₄)₃

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis

Explanation:

Step 1: Define

12.65 g Al₂(SO₄)₃

Step 2: Identify Conversions

Molar Mass of Al - 26.98 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol

Step 3: Convert

$12.65 \ g \ Al_2(SO_4)_3(\frac{1 \ mol \ Al_2(SO_4)_3}{342.17 \ g \ Al_2(SO_4)_3} )$ = 0.03697 mol Al₂(SO₄)₃

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

We already have 4 sig figs in the final answer, so no need to round.

5 0

3 years ago

For the mineral torbernite, Cu(UO2)2(PO4)2⋅8H2O, determine the total number of atoms in one formula unit

ASHA 777 [7]

Answer:

$2.47x10^{25}atoms$

Explanation:

Hello,

In this case, since the mineral torbernite has one copper atom, two uranium atoms, twenty oxygen atoms (2x2+4x2+8), two phosphorous atoms and sixteen hydrogen atoms (12x2) and therefore forty one in total, by using the Avogadro's number one is able to compute the total number of atoms in one formula unit or one mole:

$Atoms=1molCu(UO_2)_2(PO_4)_2\dot \ 8H_2O*\frac{41mol\ of \ atoms}{1molCu(UO_2)_2(PO_4)_2\dot \ 8H_2O}*\frac{6.022x10^{23}atoms}{1mol\ of \ atoms} \\\\=2.47x10^{25}atoms$

Best regards.

6 0

3 years ago

What is the ph of a 0.014 M HCL solution?

Allushta [10]

Answer:

pH $= 1.853$

Explanation:

For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.

$[H_3O^+] = [HCl] = 0.014$

pH $= -log [H^+] = -log [H_3O^+]$

Substituting the available values in above equation, we can say that the pH of the solution is equal to

$- log (0.014)$

pH $= 1.853$

pH of a $0.014$ M HCL solution $= 1.853$

8 0

3 years ago

A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0-L vessel at 300 K. The following equilibriu

tatyana61 [14]

Answer:

[H2] = 0.012 M

[N2] = 0.019 M

[H2O] = 0.057 M

Explanation:

The strategy here is to account for the species at equilibrium given that the concentration of [NO]=0.062M at equilibrium is known and the quantities initially present and its stoichiometry.

2NO(g) + 2H2(g) ⇒ N2(g) + 2H2O(g)

i mol 0.10 0.050 0.10

c mol -0.038 -0.038 +0019 +0.038

e mol 0.062 0.012 00.019 0.057

Since the volume of the vessel is 1.0 L, the concentrations in molarity are:

[NO] = 0.062 M

[H2] = 0.012 M

[N2] = 0.019 M

[H2O] = 0.057 M

5 0

3 years ago

White sugar and iodized salt did the resulting look same throughout?​

White sugar and iodized salt did the resulting look same throughout?