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mojhsa [17]
1 year ago
12

Which element tends to gain electrons to form an anion A. S B. Na C. Mn D. Ba

Chemistry
2 answers:
jok3333 [9.3K]1 year ago
8 0

Answer:

A.) S

Explanation:

Anions form when elements have more electrons than protons. Some elements want to gain electrons because all elements desire a full octet (8 valence electrons). That being said, some elements are closer to a full octet by gaining electrons, whereas some are closer when they give up electrons.

As a general rule, as you move to the right across the period table, the number of valence electrons an element has increases. Therefore, on the right of the periodic table, these elements have a little less than 8 valence electrons. It makes sense that these elements want to gain those last few electrons to gain a full octet, rather than giving up electrons. Sulfur (S) has 6 valence electrons (located in the 16th column). To gain a full octet, it will gain two electrons and thus become an anion.

Na, Mn, and Ba are on the left of the periodic table, so they'd rather give up electrons than gain them (to become cations).

Reptile [31]1 year ago
3 0
B it’s right answer
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1. Show that heat flows spontaneously from high temperature to low temperature in any isolated system (hint: use entropy change
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1 ) Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

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                 = Q/tc - Q/th

2) ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

Explanation:

<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

example :

Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

Place both blocks for time (t ) in an insulated system to reduce heat loss or gain to or from the environment

Check the temperature of both blocks after time ( t ) it will be observed that both blocks will have same temperature after time t ( first law of thermodynamics )

Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

<u>2) Entropy change for Decomposition of mercuric oxide </u>

2HgO (s) → 2Hg(l) + O₂ (g)

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hence ΔSdecomposition = S⁻ Hg  -  S⁻ HgO =

Δh of reaction = 181.6 KJ

Temp = 500 + 273 = 773 k

hence ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

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