The answer is sodium hydroxide
Answer:
Electrons will flow from left to right through the wire.
Pb^2+ ions will be reduccd to Pb metal.
The concentration of Sn2+ ions in the left compartment will increase.
Explanation:
Looking at the relative electrode potentials of the two metals
Sn= -0.14
Pb=-0.13
Tin is expected to function as the anode (left hand half cell) and lead as the anode (right hand half cell) tin oxidizes to sn^2+ hence its concentration increases on the left compartment while lead is reduced to ordinary lead metal on the right hand half cell . since oxidation occurs on the left hand side, electrons flow from left to right.
Actually, you do NOT need to calculate the number of moles, so you do NOT need to convert the volume and pressure. (You DO have to convert the temperature.) That's because for this problem, pV/T is constant, so the units cancel (but the temperature scale matters).
<span>200kPa * 15L / 373K = 101kPa * V / 273K </span>
<span>V = 21.7 L </span>
<span>Peer review affect research in a good way. Though you have done research time and time again, it's always best to have a colleague or someone in that field to evaluate a peer review to make sure everything in the research is 100% correct. Now some experimental results won't be trusted unless there has been peer reviewed from the scientific community.</span>