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AURORKA [14]
4 years ago
14

A bag of fruit contains 3 apples and 2 oranges and 1 banana and 4 pears.Gerald will randomly selected two pieces of fruit one at

a time from the bag and not put is back. What is the probability that the first piece of fruit Gerald selects will be a banana and the second piece of fruit will be a pear??
Mathematics
1 answer:
AVprozaik [17]4 years ago
3 0
1/4 would be the probability
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Sam has $2.25 in quarters and dimes, and the total number of coins is 12. How many quarters and how many dimes?
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N₁*$0.10 + n₂*$0.25 = $2.25

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This means that:

n₁ = 12 - n₂

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12*$0.10 - n₂*$0.10 + n₂*$0.25 = $2.25

$1.20 + n₂*$0.05*(5-2) = $2.25

$1.20 + n₂*$0.05*3 = $2.25

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n₂ = ($1.05)/($0.15)

n₂ = 7

If n₂ = 7:

n₁ + 7 = 12

Therefore, n₁ = 5.

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Answer:

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8 0
3 years ago
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Answer:

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