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3 years ago

15

blair cuts a ribbon into 2 equal pieces. then she cut 4 inches off one piece. that piece is now 5 inches long. what was the leng

th of the original ribbon?

1 answer:

Ksju [112]3 years ago

4 0

The original ribbon was 18 inches long.
hope it helps

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Claire buys a jacket that originally cost $76, the price is marked down 25%and Claire has a coupon to further reduce the price b

Sauron [17]

Answer:

$51.30

Step-by-step explanation:

76 decrease 25% =

76 × (1 - 25%) = 76 × (1 - 0.25) = 57

57 decrease 10% =

57 × (1 - 10%) = 57 × (1 - 0.1) = 51.3

5 0

3 years ago

At Appliance Market, a salesperson sells a dishwasher for $569. She gets a commission rate of 18 percent. Which expression repre

posledela

569/x=100/18
multiply both sides of the equation
569=5.55556
now we divide
569/5.55556
102.42=x

18% of 569=102.42

4 0

4 years ago

Read 2 more answers

Name the vertex of <4<br><br>

Licemer1 [7]

Hey there!

The vertex of any angle refers to the place where the angles forms (the middle most point in an angle). In <4, <u>U </u>is the vertex of the angle.

Hope it helps ya!

8 0

3 years ago

hus, D satisfying (ABC)DequalsI exists. Why does the expression for D found above also satisfy D(ABC)equalsI, thereby showing

Assoli18 [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

First Question

Option A is correct

Second Question

Option C is correct

Third Question

$D = A^{-1} * B^{-1} * C^{-1}$

Fourth Question

So substituting for D in (ABC) D = I

$(ABC) * A^{-1} * B^{-1} * C^{-1} = I$

$I = I$

This proof that ABC is invertible

Step-by-step explanation:

From the question we are told that

A , B and C are invertible which means that $A^{-1} , B^{-1}, C^{-1}$ exist

Now

From the question

(ABC) D = I

Where I is an identity matrix

Now when we multiply both sides by $A^{-1}$ we have

$A^{-1} A BCD = A^{-1} * I$

$IBCD = A^{-1}$

Now when we multiply both sides by $B^{-1}$ we have

$B^{-1 } *I BCD = A^{-1} * B^{-1}$

$I CD = A^{-1} * B^{-1}$

Now when we multiply both sides by $C^{-1}$ we have

$C^{-1} * I CD = A^{-1} * B^{-1} * C^{-1}$

$I D = A^{-1} * B^{-1} * C^{-1}$

$D = A^{-1} * B^{-1} * C^{-1}$

So substituting for D in the above equation

$(ABC) * A^{-1} * B^{-1} * C^{-1} = I$

$I = I$

This proof that ABC is invertible

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3 years ago

inna [77]

Marco is 10 times greater than salima

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3 years ago