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2 years ago

Shape 1 and shape 2 are plotted on a coordinate plane. Which statement about the shapes is true?

Mathematics

1 answer:

Nataliya [291]2 years ago

7 0

Answer:

Step-by-step explanation:

if the shapes were rotated it would be easier to prove that the shape are congruent. Hope this helps :)

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Select the system that has the same solution as -2x+2y=-5 5x- 6y =8

stiks02 [169]

Answer:

-2x+2y=-5 is equal to x=y+ 5 /2

5x- 6y =8 is equal to x= 6 /5 y+ 8 /5

Step-by-step explanation:

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3 years ago

For example, for a circle of diameter 4 cm, the circumference is approximately<br> cm.

Simora [160]

Answer:

the diameter is 4 cm which means the radius is 2 cm. Diameter divided by two will give you the radius. The formulae for circumference is 2 π⋅r. So the circumference would be 4 π.

Step-by-step explanation:

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3 years ago

In circle O, and are diameters. The measure of arc DC is 50°.

bonufazy [111]

Answer:

220

Step-by-step explanation:

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3 years ago

Read 2 more answers

If 5/8ths is equal to $531.25 what is the remaining portion of the number.

Nimfa-mama [501]

5/8 = .625
531.25 / .625 = 850
850 - 531.25 = $318.75

7 0

3 years ago

A home security system is designed to have a 99% reliability rate. Suppose that nine homes equipped with this system experience

bulgar [2K]

Answer:

a) $P(X \geq 1) = 1-P(X$

$P(X=0)=(9C0)(0.99)^0 (1-0.99)^{9-0}=1x10^{-18}$

And replacing we got:

$P(X \geq 1) =1 -1x10^{-18} \approx 1$

b) $P(X=7)=(9C7)(0.99)^7 (1-0.99)^{9-7}=0.003355$

$P(X=8)=(9C8)(0.99)^8 (1-0.99)^{9-8}=0.083047$

$P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517$

And adding we got:

$P(X \geq 7) = 0.003355+0.083047+0.913517 =0.99992$

c) $P(X \leq 8) =1 -P(X>8) = 1-P(X=9)$

$P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517$

And replacing we got:

$P(X \leq 8)= 1-0.913517=0.086483$

Step-by-step explanation:

Let X the random variable of interest "numebr of times that an alarm is triggered", on this case we now that:

$X \sim Binom(n=9, p=0.99)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

We want to find this probability:

$P(X \geq 1) = 1-P(X$

$P(X=0)=(9C0)(0.99)^0 (1-0.99)^{9-0}=1x10^{-18}$

And replacing we got:

$P(X \geq 1) =1 -1x10^{-18} \approx 1$

Part b

$P(X \geq 7)= P(X=7) +P(X=8)+ P(X=9)$

$P(X=7)=(9C7)(0.99)^7 (1-0.99)^{9-7}=0.003355$

$P(X=8)=(9C8)(0.99)^8 (1-0.99)^{9-8}=0.083047$

$P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517$

And adding we got:

$P(X \geq 7) = 0.003355+0.083047+0.913517 =0.99992$

Part c

$P(X \leq 8) =1 -P(X>8) = 1-P(X=9)$

$P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517$

And replacing we got:

$P(X \leq 8)= 1-0.913517=0.086483$

4 0

3 years ago