These days, scientists all over the world use a standard system of measurements. It's the SI or metric system.
What about scientists in the United States, Liberia, and Burma ?
These three countries are the only ones in the world that haven't
adopted the metric system. What do THEY do ?
Easy. When scientists in those countries are off work, they use the
inches, yards, feet, quarts, miles and gallons that everybody around
them is using. But when they go to work, they use the same metric
system that everyone else in the world is using.
No because there must be an even # if their is an even amount one of the forces isn’t being cancelled
Answer:
The displacement was 320 meters.
Explanation:
Assuming projectile motion and zero initial speed (i.e., the object was dropped, not thrown down), you can calculate the displacement using the kinematic equation:

The displacement was 320 meters.
Answer: C Heat Transfer, E Addition of Volatiles and A Decompression
Explanation:
- Decompression melting takes place within Earth when a body of rock is held at approximately the same temperature but the pressure is reduced.
Answer:
Part a)

Part b)

Part c)

Part d)

Explanation:
Part a)
While bucket is falling downwards we have force equation of the bucket given as

for uniform cylinder we will have

so we have


now we have




now we have


Part b)
speed of the bucket can be found using kinematics
so we have



Part c)
now in order to find the time of fall we can use another equation



Part d)
as we know that cylinder is at rest and not moving downwards
so here we can use force balance


