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3 years ago

An optimistic outlook is related to:

Physics

2 answers:

zhuklara [117]3 years ago

8 0

An open minded person

Oksanka [162]3 years ago

6 0

PLZ ANSWER MY LATEST QUESTION

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SOMEONE HELP ME PLSS

lara31 [8.8K]

1. 2500/60 joules/sec
2. 2,500Nm

7 0

2 years ago

Read 2 more answers

If you stood on a planet with four times the mass of Earth, and twice Earth's radius, how much would you weigh?

nikdorinn [45]

Answer:

1/4 times your earth's weight

Explanation:

assuming the Mass of earth = M

Radius of earth = R

∴ the mass of the planet= 4M

the radius of the planet = 4R

gravitational force of earth is given as = $\frac{GM}{R^{2} }$

where G is the gravitational constant

Gravitational force of the planet = $\frac{G4M}{(4R)^{2} }$

= $\frac{G4M}{16R^{2} }$

= $\frac{GM}{4R^{2} }$

recall, gravitational force of earth is given as = $\frac{GM}{R^{2} }$

∴Gravitational force of planet = 1/4 times the gravitational force of the earth

you would weigh 1/4 times your earth's weight

3 0

3 years ago

In the picture of a planet in orbit around its star area a is double that of area b. What is true of the time the planet takes t

aalyn [17]

The Kepler's laws predict the planetary motion, so there are three laws for this, namely:

1. The orbit of a planet is an ellipse with the Sun (the sun is a star!) at one of the two focus.

2. A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time.

3. The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit.

So, let's use second law. The Sun sweeps out equal areas during equal intervals of time means that if A = B, the time the planet takes to travel A1A2 is equal to the time the planet takes to travel B1B2, but given that A = 2B, then takes twice the time to travel A1A2 compared to B1B2.

8 0

3 years ago

A train starts from rest and travels for 5.0 s with a uniform acceleration of 1.5 m/s2. What is the final velocity of the train?

alexandr1967 [171]

Answer:

Final speed of the train is 7.5 m/s

Explanation:

It is given that,

Uniform acceleration of the train is, a = 1.5 m/s²

It starts from rest and travels for 5.0 s. We have to find the final velocity of the train. By using first equation of motion as :

$v=u+at$

Here, train starts from rest so, u = 0

$v=0+1.5\ m/s^2\times 5\ s$

v = 7.5 m/s

So, the final velocity of the train is 7.5 m/s. Hence, this is the required solution.

7 0

2 years ago

Read 2 more answers

A small lab cart and one of larger mass collide and rebound off each other. Which of them has the greater average force on it du

Elza [17]

When a small cart collide with a large mass then during collision they must be in contact with each other for some interval of time

During this contact interval we can say they will exert normal force on each other

This normal force is always equal and opposite on two balls which means this force will follow Newton's III law

It will be same in magnitude but opposite in the direction

So here correct answer would be

<u><em>They both experience the same magnitude of the collision force.</em></u>

4 0

2 years ago