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katrin2010 [14]
3 years ago
10

A crate weighing 523 N rests on a plank that makes a 22.0  angle with the ground. Find the components of the crate's weight for

ce parallel and perpendicular to the plank. ( Fgx = –196 N, Fgy = –485 N)
Physics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

Explanation:

The weight of the crate will e equal to its normal reaction R

Since R = mgsin theta = W

W = mgsintheta ( resolved along the vertical perpendicular to the plank

Fy = 523sin22°

Fy = 195.92N

Since the weight is acting along the negative y direction,

Fy = -195.92N

The force parallel to the plank will be the force acting in the horizontal direction.

Fx = Fcos theta

Fx = 523cos 22°

Fx = 484.9N

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3 0
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Question:
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Answer:

She can swing 1.0 m high.

Explanation:

Hi there!

The mechanical energy of Jane (ME) can be calculated by adding her gravitational potential (PE) plus her kinetic energy (KE).

The kinetic energy is calculated as follows:

KE = 1/2 · m · v²

And the potential energy:

PE = m · g · h

Where:

m = mass of Jane.

v = velocity.

g = acceleration due to gravity (9.8 m/s²).

h = height.

Then:

ME = KE + PE

Initially, Jane is running on the surface on which we assume that the gravitational potential energy of Jane is zero (the height is zero). Then:

ME = KE + PE      (PE = 0)

ME = KE

ME = 1/2 · m · (4.5 m/s)²

ME = m · 10.125 m²/s²

When Jane reaches the maximum height, its velocity is zero (all the kinetic energy was converted into potential energy). Then, the mechanical energy will be:

ME = KE + PE      (KE = 0)

ME = PE

ME = m · 9.8 m/s² · h

Then, equallizing both expressions of ME and solving for h:

m · 10.125 m²/s² =  m · 9.8 m/s² · h

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She can swing 1.0 m high (if we neglect dissipative forces such as air resistance).

6 0
3 years ago
The mass of a star is 1.210×1031 kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter su
balandron [24]

The new period will be 2.486 days.

<h3>What is the period?</h3>

The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.

Given data;

Mass of a star,m= 1.210×10³¹ kg

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D' = 0.350 D

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From the law of conservation of angular momentum;

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Hence, the new period will be 2.486 days.

To learn more about the period, refer to the link;

brainly.com/question/569003

#SPJ1

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