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2 years ago

Para que el calor sea transmitido por conducción los cuerpos deben tocarse? verdadero o falso

Physics

1 answer:

dybincka [34]2 years ago

7 0

Answer:

verdadero

Explanation:

Conducción:Es la más sencilla de entender, consiste en la transferencia de calor entre dos puntos de un cuerpo que se encuentran a diferente temperatura, sin que se produzca transferencia de materia entre ellos.

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How much weight can a man lift in the jupiter if he can lift 100kg on the earth.calculate

Nuetrik [128]

Answer:

<h3>2479 Newton</h3>

Solution,

Mass=100 kg

Acceleration due to gravity(g)=24.79 m/s^2

Now,.

 $weight = m \times g \\ \: \: \: \: \: \: \: \: \: \: = 100 \times 24.79 \\ \: \: \: \: \: \: = 2479 \: newton$ 

hope this helps ..

Good luck on your assignment..

5 0

3 years ago

A weight of 1400 pounds is suspended from two cables as shown in the figure. What is the tension in the left cable? _________ po

juin [17]

Answer:

Following are the solution to this question:

Explanation:

Law:

$\to \theta= 180^{\circ}- 50^{\circ}- 25^{\circ}$

$= 180^{\circ}- 75^{\circ}\\\\= 105^{\circ}$

$\to \frac{T_{L}}{\sin (90+50)}= \frac{T_{R}}{\sin (25+90)}=\frac{1400}{\sin (105)}$

$\to T_L=931.65 \ pounds \\\\ \to T_R=1313.59 \ pounds \\\\$

4 0

3 years ago

A car enters a horizontal, curved roadbed of radius 50 m. the coefficient of static friction between the tires and the roadbed i

UkoKoshka [18]

Previous results tell us the speed (v) is given in terms of the coefficient of friction (k) and the radius of the curve (r) as
v = √(kgr)
v = √(0.20·9.8 m/s²·50 m)
= 7√2 m/s ≈ 9.90 m/s

6 0

3 years ago

Read 2 more answers

An ideal refrigerator does 130. 0 j of work to remove 780. 0 j of heat from its cold compartment during each cycle. what is the

zheka24 [161]

The refrigerator's coefficient of performance is 6.

The heat extracted from the cold reservoir Q cold (i.e., inside a refrigerator) divided by the work W required to remove the heat is known as the coefficient of performance, or COP, of a refrigerator (i.e., the work done by the compressor). The required inside temperature and the outside temperature have a significant impact on the COP.

As the inside temperature of the refrigerator decreases, its coefficient of performance decreases. The coefficient of performance (COP) of refrigeration is always more than 1.

The heat produced in the cold compartment, H = 780.0 J

Work done in ideal refrigerator, W = 130.0 J

Refrigerator's coefficient of performance = H/W

= 780/130

= 6

Therefore, the refrigerator's coefficient of performance is 6.

Energy conservation requires the exhaust heat to be = 780 + 130

= 910 J

Learn more about coefficient here:

brainly.com/question/18915846

#SPJ4

5 0

2 years ago

The element that has an average amu of 40 is represented by the symbol Zr on the Periodic Table of Elements. True False Question

Gnom [1K]

Answer:

False

Explanation:

Becuase the average amu of 40 is represented

6 0

3 years ago