Answer:
Altitude
Step-by-step explanation:
An altitude of a triangle always extends from a vertex to the opposite base (side) of the triangle, and it is always at a right angle. It is also known as the "height".
Answer
Multipy all of them
Step-by-step explanation:
mulitiply all of them
Answer:
The vertex is (2,1)
Step-by-step explanation:
ƒ(x) = –x^2 + 4x – 3
Factor out the negative
= -(x^2 -4x+3)
Factor
What 2 numbers multiply to +3 and add to -4
-3*-1 = 3
-3+-1 = -4
f(x) = -( x-3)(x-1)
Find the zeros
0 = -( x-3)(x-1)
0 = x-3 0 = x-1
x=3 x=1
The x value of the vertex is 1/2 way between the two zeros
(3+1)/2 = 4/2 =2
To find the y value, substitute x=2 in
f(2) = -( 2-3)(2-1)
=-(-1)(1) = 1
The vertex is (2,1)
Answer:
Ok, we have a system of equations:
6*x + 3*y = 6*x*y
2*x + 4*y = 5*x*y
First, we want to isolate one of the variables,
As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:
(6*x + 3*y)/(2*x + 4*y) = 6/5
now we isolate one off the variables:
6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y
x*(6 - 12/5) = y*(24/5 - 3)
x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y
Now we can replace it in the first equation:
6*x + 3*y = 6*x*y
6*(0.5*y) + 3*y = 6*(0.5*y)*y
3*y + 3*y = 3*y^2
3*y^2 - 6*y = 0
Now we can find the solutions of that quadratic equation as:

So we have two solutions
y = 0
y = 2.
Suppose that we select the solution y = 0
Then, using one of the equations we can find the value of x:
2*x + 4*0 = 5*x*0
2*x = 0
x = 0
(0, 0) is a solution
if we select the other solution, y = 2.
2*x + 4*2 = 5*x*2
2*x + 8 = 10*x
8 = (10 - 2)*x = 8x
x = 1.
(1, 2) is other solution